Answer:
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Answer:
235/92U+10n→144/54Xe+90/38Sr+2/10n
Explanation:
- The nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90 is represented by;
235/92U+10n→144/54Xe+90/38Sr+2/10n
- In nuclear fission reactions a heavy nuclide is split into two light nuclides and is coupled by the release of energy.
Iron (iii) chloride is obtained by vapor condensation from the reaction between chlorine gas and iron fillings.
<h3>How can iron (iii) chloride be formed from iron fillings?</h3>
Iron (ii) chloride can be formed from iron fillings in the laboratory as follows:
- Iron fillings + Cl₂ → FeCl₃
Chlorine gas is introduced into a reaction vessel containing iron fillings and the iron (iii) chloride vapor formed is obtained by condensation.
In conclusion, iron (iii) chloride is formed by the the direct combination of iron fillings and chlorine gas.
Learn more about iron (iii) chloride at: brainly.com/question/14653649
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<span>2.28 kg x 213 kJ/kg = 486 kJ = 4.86E+05 J</span>
