All categories

3 years ago

How many moles of N are in 0.241 g of N2O?

Chemistry

2 answers:

gtnhenbr [62]3 years ago

6 0

0.00547 moles of N.

eduard3 years ago

6 0

Answer:

Explanation:

Calculate the molar mass of the $N_{2}O$ :

Molar mass N = $14\frac{g}{mol}$

Molar mass O = $16\frac{g}{mol}$

Molar mass $N_{2}O$ = 2*(Molar mass of N) + Molar mass of O

Molar mass $N_{2}O$ = $2*(14\frac{g}{mol})+16\frac{g}{mol}$

Molar mass $N_{2}O$ = $44\frac{g}{mol}$

Calculate the number of moles of N in 0.241g of $N_{2}O$ :

$0.241gN_{2}O*\frac{1molN_{2}O}{44gN_{2}O}*\frac{2molesN}{1molN_{2}O}=0.01molesN$

You might be interested in

Help please.

Alexxx [7]

Answer:

this is my old account and these still dont have answers

Explanation:

8 0

3 years ago

Help

Jet001 [13]

Answer:

Explanation:

The formation of ion occurs when an atom that is said to be neutral gains or losses electrons.

At the time it gains electrons, it is regarded that a negative ion (anion) is formed.

When it loses electron, it is regarded that a positive ion (cation) is formed.

Atomic number = No of protons and electrons occurring in a neutral atom.

Given that:

Protons = 14

electron = 18

Net Charge = no of proton - no of electron

= 14 - 18

= -4

Mass number = 14 + 15 = 29

So, the chemical symbol = $Si^{-4}$

For ion with

27 proton, 32 neutrons and 25 electrons

Net charge = 27 - 25

= +2

Mass number = 27 + 32 = 59

Thus, the chemical symbol = $Co^{+2}$

6 0

3 years ago

What is the mole fraction of solute and the molal concentration for an aqueous solution that is 20.0% NaOH by mass?

never [62]

Let's assume we have 100 grams of this solution, and therefore 20.0 grams of NaOH, and 80.0 grams of water.

NaOH has a molar mass of 40.00 grams/mole, so we can convert NaOH to moles: (20.0 grams of NaOH) * (1 mole NaOH/40.00 grams NaOH) = 0.500 moles NaOH.

Next, we have a molar mass of water of 18.02 g/mol, so we can convert water to moles:

80.0 grams H2O * (1 mole H2O/18.02 grams) = 4.44 moles H2O
The mole fraction of NaOH is the moles of NaOH over the total moles of all parts of the solution. Therefore:

(0.500 moles NaOH)/(0.500 moles + 4.44 moles) = 0.101
0.101 = mole fraction of solute

The molal concentration is defined as the number of moles of solute over the number of kilograms of solvent (water).
We have 0.500 moles of NaOH, and 0.0800 kg of water, so it becomes:
(0.500 moles NaOH)/(0.0800 kg H2O solvent) = 6.25 molal solution

8 0

4 years ago

How do i get a girl friend ?

madam [21]

Answer:

1. Try an actual dating site

2. Be yourself

3. Go outside and meet people

8 0

3 years ago

Read 2 more answers

Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 2.80g

oee [108]

Answer:

54%

Explanation:

The balanced equation is:

$2 CH_{3}(CH_{2})_{6}CH_{3} + 25 O_{2} = 16 CO_{2} + 18 H_{2}O$

The first step is to determine the limiting reactant. For this, we calculate the moles of each given component and divide the result for the stoichiometric coefficient.

3.4 g octane / 114.23 g/mol = 0.030 mol octane

0.030 mol octane/2=0.015

5.9 g O2 / 32 g/mol = 0.18 mol O2

0.18 mol O2/25= 0.0074 mol

The lower number, in this case oxygen, is the limiting reactant. The value corresponds to the theoretical yield of the reaction.

Similarly, the real yield is calculated from the product.

2.80 g CO2/ 44.01 g/mol = 0.0636 mol CO2

0.0636 mol CO2/16 = 0.00398 mol

The percent yield is the ratio of the 2 multiplied by a hundred, then

Percent yield= 0.0398/0.0074 *100 = 54%

3 0

3 years ago