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JulijaS [17]
3 years ago
10

How many moles of N are in 0.241 g of N2O?

Chemistry
2 answers:
gtnhenbr [62]3 years ago
6 0
0.00547 moles of N.
eduard3 years ago
6 0

Answer:

Explanation:

Calculate the molar mass of the N_{2}O:

Molar mass N = 14\frac{g}{mol}

Molar mass O = 16\frac{g}{mol}

Molar mass N_{2}O = 2*(Molar mass of N) + Molar mass of O

Molar mass N_{2}O = 2*(14\frac{g}{mol})+16\frac{g}{mol}

Molar mass N_{2}O = 44\frac{g}{mol}

Calculate the number of moles of N in 0.241g of N_{2}O:

0.241gN_{2}O*\frac{1molN_{2}O}{44gN_{2}O}*\frac{2molesN}{1molN_{2}O}=0.01molesN

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iragen [17]
The answer is 2H2 + O2----> 2H2O
5 0
3 years ago
at what temperature will you find more potassium nitrate(kno3) in 100 g of H2O . In other words at which temperature will you ha
Oksana_A [137]
The answer to this question would be: <span>85c 
</span>Solubility is influenced by the temperature of the molecule. Higher temperature will result in a higher solubility. That is why brewing using hot water will be easier than using cold water. Higher temperature also means higher reaction rate.
4 0
3 years ago
A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K. What is the new press
Sindrei [870]

Answer:

1.47 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 32.4 L
  • Initial pressure (P₁): 1 atm (standard pressure)
  • Initial temperature (T₁): 273 K (standard temperature)
  • Final volume (V₂): 28.4 L
  • Final pressure (P₂): ?
  • Final temperature (T₂): 352 K

Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

7 0
3 years ago
If 2,035 cal of heat is added to a 500.0 g sample of water at 35.0°C, what is the final
Lynna [10]

Answer:

39.1 °C

Explanation:

Recall the equation for specific heat:

q=mc \Delta T\\

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.

You should know that the specific heat of water is 1 cal/g/C.

Using the information in the question:

2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07

The final temperature is about 39.1 °C.

5 0
3 years ago
30.0 ml of an hf solution were titrated with 22.15 ml of a 0.122 m koh solution to reach the equivalence point. what is the mola
a_sh-v [17]
Answer is: molarity of hydrofluoric solution is 0.09 M.

Chemical reaction: HF(aq) + KOH(aq) → KF(aq) + H₂O(l).
V(HF) = 30.0 mL.
c(KOH) = 0.122 M.
V(KOH) = 22.15 mL:
c(HF) = ?.
From chemical reaction: n(HF) : n(KOH) = 1 : 1.
n(HF) = n(KOH).
c(HF) · V(HF) = c(KOH) · V(KOH).
c(HF) = c(KOH) · V(KOH) ÷ V(HF).
c(HF) = 0.122 M · 22.15 mL ÷ 30 mL:
c(HF) = 0.09 M.
8 0
3 years ago
Read 2 more answers
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