Answer: K only has 1 valence electron. It will leave with only a little effort, leaving behind a positively charged K^+1 atom.
Explanation: A neutral potassium atom has 19 total electrons. But only 1 of them is in potassium's valence shell. Valence shell means the outermost s and p orbitals. Potasium's electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1. The 4s orbital is the only orbital in the 4th energy level. So it has a valency of 1. This means this electron will be the most likely to leave, since it is the lone electron in the oyutermost energy level (4). When that electron leaves, the charge on the atom go up by 1. The atom now has a full valence shell of 3s^2 3p^6, the same as argon, Ar.
Answer:
The answer to your question is: 24 grams of D
Explanation:
To answer this question we need to remember the Lavoisier law of conservation of mass, which says that in a chemical reaction matter is neither created nor destroyed.
This means that the amount of matter stays the same.
Then, the reaction is
A + B ⇒ C + D
26 g 12 g 14 g x
mass
of reactants 38 g ? mass of products, but it must be
equal to the mass of products
Then 14g + x = 38
x = 38 - 14
x = 24 g of D
Complete question is;
Which of the following object would take you the greatest amount of force to accelerate.
A) a soccer ball with a mass of 0.5 kg
B) a refrigerator with a mass of 200 kg, C) a bike with a mass of 25 kg
D) a car with a mass of 5,000 kg,
Answer:
D) a car with a mass of 5,000 kg
Explanation:
Formula for force is;
F = ma
Where;
F is force
m is mass
a is acceleration
Now, Force is directly proportional to the acceleration and mass.
Thus, the higher the mass, the greater the force.
Thus, the object that will require the most force is the one that has the highest mass.
Looking at the options, the one with the highest mass is option D.
First let's find out the oxidation number of Fe in K₄[Fe(CN)₆] compound.
The oxidation number of cation, K is +1. Hence, the total charge of the anion, [Fe(CN)₆] is -4. CN has charge has -1. There are 6 CN in anion. Let's assume the oxidation number of Fe is 'a'.
Sum of the oxidation numbers of each element = Charge of the compound
a + 6 x (-1) = -4
a -6 = -4
a = +2
Hence, oxidation number of Fe in [Fe(CN)₆]⁴⁻ is +2.
Now Fe has the atomic number as 26. Hence, number of electrons in Fe at ground state is 26.
Electron configuration = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶ 4s² = [Ar] 3d⁶ 4s²
When making Fe²⁺, Fe releases 2 electrons. Hence, the number of electrons in Fe²⁺ is 26 - 2 = 24.
Hence, the electron configuration of Fe²⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶
= [Ar] 3d⁶
Hence, the number of 3d electrons of Fe in K₄[Fe(CN)₆] compound is 6.
