Step-by-step answer:
The first step in solving a problem of geometry and trigonometry is to draw a diagram, with all the given information in it. The attached image does just that.
Here, we have (horizontal) distance of building to the tower is 400'.
We see two right triangles, each with a leg of 400' (horizontal).
The vertical distances are denoted h1 and h2 for the angles of elevation 24 and 20 degrees respectively.
Using the definition of tangent, we have
h1= 400tan24=178.1
h2=400tan20=145.6
The height of the tower is therefore h1+h2=178.1+145.6=323.7 feet
From 100 to 80 is 8/10, so the recursive formula is
an=a(n-1)*1/8
or
an= a1*1/8(n-1)
an=a1*(n-1)/8
Answer:
The length of s is 5.1 inches to the nearest tenth of an inch
Step-by-step explanation:
In Δ RST
∵ t is the opposite side to ∠T
∵ r is the opposite side to ∠R
∵ s is the opposite side to ∠S
→ To find s let us use the cosine rule
∴ s² = t² + r² - 2 × t × r × cos∠S
∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°
→ Substitute them in the rule above
∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)
∴ s² = 16.81 + 50.41 - 41.1677568
∴ s² = 26.0522432
→ Take √ for both sides
∴ s = 5.10413981
→ Round it to the nearest tenth
∴ s = 5.1 inches
∴ The length of s is 5.1 inches to the nearest tenth of an inch
First, Joe started the water and it was at full force. He filled it up to 9 inches. It took him 2 minutes to get to 9 inches. Then, he stopped it for 2 minutes because his mom called him to get a bar of soap. The water level was still at 9 inches when he stopped it. Then, he put the water to come down slowly because he wasn’t sure how much more he needed. He let the water go for 2 minutes. Then, he stopped the water when it was at 12 inches of water. He sat in the bath for 5 minutes until he decided he was to cold so he hopped out. The water then drained really fast. From 12 inches to 0 inches it took the bath 3 minutes.
