2 sqrt3 + 3 sqrt3
= 5 sqrt3
Since this contains the irrational sqrt3 it is irrational
Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
The answer is C, because there are two different numbers correlated to the same number on the Y side. The table does not represent a function.
Answer:
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