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alexandr402 [8]

3 years ago

12

bob left work and traveled to school at an average speed of 25 mph. if it took bob 35 minutes to reach school, how far is bobs s

chool from his place of work

1 answer:

BabaBlast [244]3 years ago

6 0

Convert minutes to hour(35/60=.58 then multiply 25mph to get 14.5 miles

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Which statement is true about the equations –3x + 4y = 12 and x – y = 1?

Firlakuza [10]

-3x + 4y = 12
x - y = 1....x = y + 1

-3(y + 1) + 4y = 12
-3y - 3 + 4y = 12
-3y + 4y = 12 + 3
y = 15

x - y = 1
x - 15 = 1
x = 1 + 15
x = 16

one solution (16,15)

6 0

3 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

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4 years ago

The mean number of travel days per year for salespeople employed by three hardware distributors needs to be estimated with a 0.9

bearhunter [10]

Answer:

133

Step-by-step explanation:

7 0

3 years ago

Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

notka56 [123]

A= (1/2) b*h
h=3 sqrt3
A= (1/2)*6*3sqrt3
A= 9sqrt3 square inches

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3 years ago