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ki77a [65]
3 years ago
7

If 5 burgers and 4 orders of fries cost $30.76 and 8 burgers and 6 orders of fries cost $48.28, what is the cost of a burger and

what is the cost of an order of fries?​
Mathematics
1 answer:
padilas [110]3 years ago
3 0

Step-by-step explanation:

5B+4F= $30.76

×3

15B+12F= $92.28

----------------------------

8B+6F= $48.28

×2

16B+12F= $96.56

----------------------------

Cost of one burger:

$97.56-$92.28= $4.28 (final ans)

Cost of one fries:

$30.76-5($4.28)= $9.36 (for 5 fries)

$9.36÷5= $1.87 (final ans)

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Seven more than a number
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4 years ago
What is the conjecture sentence for the pattern 1, ,4, 9 ,16?
nexus9112 [7]

Answer:

Square numbers

Step-by-step explanation:

if 1 is squared, you get 1.

if 2 is squared, you get 4.

if 3 is squared, you get 9.

if 4 is squared, you get 16.

And thus square numbers.

8 0
3 years ago
Joey father stops at the gas station to buy gas the car has a 16 gallon tank and the. Fuel gauge says there is 3/8 of a tank of
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Answer:

\frac{3}{8} *16=6 gallons

Step-by-step explanation:


3 0
3 years ago
Jordan invested $600 in a savings account. The interest rate is 6% per year. Find the simple interest earned in 3 years. Then fi
olga2289 [7]

In 3 years $108 in interest is earned

principle + interest = $708

8 0
3 years ago
The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3
Alekssandra [29.7K]

Answer:

9\pi \text{ cubic meters per hour}

Step-by-step explanation:

Since, the surface area of a cylinder,

A= 2\pi r^2 + 2\pi rh  ................(1)

Where,

r = radius,

h = height,

If A= 36\pi\text{ square meters}, h = 3\text{ meters}

36\pi = 2\pi r^2 + 2\pi r(3)

18 = r^2 + 3r

\implies r^2 + 3r - 18=0

r^2 + 6r - 3r - 18 = 0     ( by middle term splitting )

r(r+6)-3(r+6)=0

(r-3)(r+6)=0

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})

∵ h = constant, ⇒ dh/dt = 0,

\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}

We have, \frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}

9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}

9\pi = (12\pi + 6\pi )\frac{dr}{dt}

9\pi = 18\pi \frac{dr}{dt}

\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}

Now,

Volume of a cylinder,

V=\pi r^2 h

Differentiating w. r. t. t,

\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}

6 0
3 years ago
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