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3 years ago

From 4a + 7b - 12c subtract 8a - 9b + 12d.

Mathematics

1 answer:

ollegr [7]3 years ago

8 0

Answer:

-4a + 16b -12c -12d

Step-by-step explanation:

Given: From 4a + 7b - 12c subtract 8a - 9b + 12d.

We are given two algebraic expression. We can add/subtract only the like terms.

(4a + 7b -12c) - (8a -9b +12d)

Now we have distribute the negative sign inside the second expression (8a -9b +12b). If we do, the sign changes.

4a + 7b -12c -8a + 9b -12d [Sign rule: -(-) = +; -(+) = -]

Now we can combine the like terms

= (4a - 8a) +(7b + 9b) -12c -12d

= -4a + 16b -12c -12d

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Answer:

tan 10 degrees.

Step-by-step explanation:

tan x = cot (90 - x) so:

cot 80 = cot (90 - 10)

= tan 10.

8 0

3 years ago

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BaLLatris [955]

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4 years ago

Read 2 more answers

If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

Pie

Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

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Replace $n+1$ with $n$ , so that the series is equivalent to

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}$

and notice that

$\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}$

Recall that for $|x|$ , we have

$\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}$

which means

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}$
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3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.