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professor190 [17]
3 years ago
10

One reaction that destroys o3 molecules in the stratosphere is

Chemistry
1 answer:
Sidana [21]3 years ago
7 0
One reaction that destroys o3 molecules in the stratosphere is when an ozone molecule combines with an oxygen atom to form two oxygen molecules, or through certain chemical reactions involving molecules containing hydrogen, nitrogen, chlorine, or bromine atoms. The atmosphere maintains a natural balance between ozone formation and destruction.
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Which of the following gives the definition of ion-dipole attraction? Select the correct answer below: O a. lon-dipole attractio
frez [133]

Answer:

D

Explanation:

Anions are attracted to the positive end of a dipole, while the cations are attracted to the negative end. As the size of the dipole moment or the ionic charge increases, the vastness of the attraction also increases. This type of attraction is important for solutions of ionic substances in polar liquids.

6 0
3 years ago
Which statement describes characteristics of earthquakes occurring along divergent plate boundaries?
IgorC [24]
B
. They are large and occur at shallow depths near the where the plates diverge.
7 0
3 years ago
How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
3 years ago
What are the necessary ingredients for photosynthesis
Eduardwww [97]

Answer:

Answer is water, carbon dioxide, and energy, which yields glucose and oxygen, as in the well-known formula: 6 H2O + 6 CO2 + Energy = C6H12O6 + 6 O2. Hope it helps!

8 0
3 years ago
Read 2 more answers
An element has an atomic number of 18 and an atomic mass of 40. The number of neutrons in the nucleus of an atom of this element
Vikentia [17]

Answer: 22 neutrons

Explanation: 40 is the mass number = atomic mass = total number of protons and neutrons in atomic nucleus

18 is the number of protons in the nucleus of this atom

Then 40 - 18 = 22 neutrons

and this is Argon

7 0
2 years ago
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