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Anarel [89]
3 years ago
8

What is the concentration of a solution with a volume of 2.5 liters containing 600 grams of calcium phosphate?​

Chemistry
1 answer:
trapecia [35]3 years ago
7 0

Answer:

1.12M

Explanation:

Given parameters:

Volume of solution  = 2.5L

Mass of Calcium phosphate  = 600g

Unknown:

Concentration  = ?

Solution:

Concentration is the number of moles of solute in a particular solution.

Now, we find the number of moles of the calcium phosphate from the given mass;

        Formula of calcium phosphate  = Ca₃PO₄

         molar mass = 3(40) + 31 + 4(16) = 215g/mol  

Number of moles of  Ca₃PO₄  = \frac{600}{215}   = 2.79moles

   Now;

  Concentration  = \frac{Number of moles }{volume }  

 Concentration  = \frac{2.79}{2.5}   = 1.12M

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Answer:

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Explanation:

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3 years ago
The notation for the nuclide 13755Cs gives information about
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5 0
3 years ago
Science is based primarily on peoples opinions and views of the subject matter.
kvv77 [185]

Answer:

False

Explanation:

Science is not based on primarily on peoples opinions and views of the subject matter whereas science is based on empirical observations and research for its validity.

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7 0
3 years ago
fish tank initially contains 35 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 5 l
weeeeeb [17]

Answer:

Therefore, the rate of change in the amount of salt is \frac{dx}{dt} =( 5c}{ - \frac{x }{20})

\frac{grams }{min}

Explanation:

Given:

Initial volume of water V = 35 lit

Flowing rate = 5 \frac{Lit}{min}

The rate of change in the amount of salt is given by,

   \frac{dx}{dt} = ( Rate of salt enters tank - rate of sat leaves tank )

Since tank is initially filled with water so we write that,

x(0) = 0

Let amount of salt in the solution is c,

  \frac{dx}{dt} = \frac{5c}{1 } - \frac{x(t) \times 5}{100}

  \frac{dx}{dt} =( 5c}{ - \frac{x }{20}) \frac{grams}{min}

Therefore, the rate of change in the amount of salt is \frac{dx}{dt} =( 5c}{ - \frac{x }{20})

\frac{grams }{min}

7 0
3 years ago
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