Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
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Answer:
1st 2nd or both's answer you want
Answer:
n-58
Step-by-step explanation:
Answer:
63
Step-by-step explanation:
You would add 41 + 18 + 4, which obviously gets you 63. Hope this helped!
Answer:
5/18
Step-by-step explanation:
note: 5/9 is the same as 10/18 (we get this by multiplying both numerator and denominator by 2)
hence
5/9-5/18
= 10/18 - 5/18
= (10-5) / 18
= 5/18
