Question

Here is a circle, centre O, and the tangent to the circle at the

Answer 1

Answer:

$y = \frac{ - 8}{15} x+ \frac{289}{15}$

Solution,

The equation of tangent to a circle with radius 'r' is given by:

x • x1 + y• y1= r^2

where (X1,y1) are point of intersection.

Therefore, the equation becomes:

8x+15y= (17)^2

8x+15y= 289

15y = -8x+289

y= -8/15 x +289/15

Hope this helps..

Good luck on your assignment..