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Vadim26 [7]
3 years ago
8

you have one case of soap bars in there are hundred fifty bars in the case you used 300 bars of soap per day how many cases do y

ou need in order to have enough for 7 days
Mathematics
1 answer:
butalik [34]3 years ago
6 0
Well u have to have 2 cases a day witch is 300 150+150 then times it by 7 days its 2100 bars so 2 cases would be 1050 ? I think I'm sure
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Find m angle WVX.Need help <br>​
fredd [130]

Answer:

D.51.34°

Step-by-step explanation:

tan(angle wvx)=WX/WV

i.e,tan(angle wvx)=5/4=1.25

i.e,angle wvx=tan⁻¹(1.25)

=51.34°

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3 years ago
Find the slope of the line that passes through the pair of points. <br> F(–6, 8), P(–6, –5)
asambeis [7]

-5-8 ÷ -6--6

-13 ÷ 6

gradient = -13/6

6 0
4 years ago
A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground. How high is the top o
DochEvi [55]

Answer:

The height of tree house is 70.71 feet

Step-by-step explanation:

We are given that A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground

Refer the attached figure

Length of rope AC = Hypotenuse =100 feet

The top of a tree house to the ground forms a 45∘ angle of elevation from the ground =\angle ACB = 45^{\circ}

We are supposed to find the height of tree house i.e.AB = Perpendicular

So, Using trigonometric ratio

Sin \theta = \frac{perpendicular}{Hypotenuse}\\Sin 45= \frac{AB}{AC}\\\frac{1}{\sqrt{2}}=\frac{AB}{100}\\100 \times \frac{1}{\sqrt{2}}=AB\\70.71=AB

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8 0
3 years ago
Consider the right triangle. What is the length of the hypotenuse?
NNADVOKAT [17]

Answer:

The answer would be 53

Step-by-step explanation:

8 0
4 years ago
The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

8 0
3 years ago
Read 2 more answers
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