Number two is quadrant 3 if you look up quadrants on a graph it will show you where each quadrant is. You can use this website symbolab for number 3.
You can use Desmosgraphing for number 4
1) Cancel out the common factor which in this case is 8 
2)First apply exponent rule 
now cancel out the common factors which are n and n+7 leaving you with 
3)Factorize 
cancel out the common factor in this case x+2 leaving you with 
4) Factorize 
cancel out the common factor in this case 3w-1 leaving you with 
5) In the picture
6)In the picture
I am REALLY tired sorry I wont be able to do the rest, I hope these are helpful :)
Where is the table,but this is what i did without the table .
first added all the numbers up and got 260
then i put each color and the total in fraction form
then i simplified:
yellow would be: 50/260=5/26
red would be: 45/260=9/52
blue would be: 65/260=13/52
orange would be: 40/260=4/26
green would be: 60/260=6/26
<span>1) supplementary angles => sum of angles' measure is 180°
Two lines intersecting creating four angles with the left obtuse angle labeled one and the acute angle to the right labeled two
= > angle 1 + angle 2 = 180°
Then those two match.
2) complementary angles => sum of the two angles = 90°
Two lines intersecting in a right angle with a square indicating a right
angle in quadrant one and a ray splitting quadrant two with a two
labeling the left angle and one labeling the angle on the right
=> angle 2 + angle 1 = 90°
Then those two match
3) vertical angles
Two parallel horizontal lines intersected by a vertical line with a
square indicating a right angle in quadrant one of the top line and a
one labeling the angle in quadrant two and two labeling quadrant four of
the top line
Those two matches because the angle label 1 and the angle label 2 are vertical angles as per the definittion.
4) adjacent angles
Two lines intersecting in a V shape with the left angle of one hundred fifty seven degrees and a bottom angle of X degrees
Those two match becasue the angle of 157° and the angle of X° are adjacent.
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