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zhenek [66]
3 years ago
15

URGENT!!! PLEASE HELP!!! It doesn't have to be detailed!!!

Mathematics
1 answer:
harina [27]3 years ago
3 0
4 and 1/4 feet is your answer my friend
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kakasveta [241]

answer: (2,1) hope this helps

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Solve the system y=x^2-1 y=x-1
Vikki [24]
That is the answer 
Have a Great day.

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4 years ago
Please help!!!!!!!!! Is for today I need helppppp
zvonat [6]

Step-by-step explanation:

5. <1 + <8 = 180degree

6. we have <1 = 24(your id number)

24+ <8 = 180

<8=180-24

<8 = 156

7. <1 = <5

8. <5 = 24

5 0
3 years ago
Actor the following expressions:<br> 10n + 15<br> GCF:<br> Check:<br> 1
ZanzabumX [31]

Answer: GCF = 5 (5 goes into both 10 and 15)

Step-by-step explanation:

10n/5= 2n

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if we factor it out it would be:

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5 0
3 years ago
A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
4 years ago
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