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2 years ago

What is the mathematical definition of the Subtraction Property of Equality?

2 answers:

6 0

I just learned this today.

In my case, You can add or subtract the same quantity from both sides and retain the equality.

For example: If $a=b$ , then $a-c=b-c$

Additive and Subtractive Property of Equality are the Same Thing

Credit to my math Teacher for this

Vinvika [58]2 years ago

4 0

When both sides of an equation have the same number subtracted from each of them, so the remaining part of the equation is still equal

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HEY YOU!! IT LOOKS LIKE I FORGOT THE QUESTION THE FIRST TIME ROUND!! Let's TRY AGAIN FOR THE BRAINLIEST SHALL WE!!

Vlad1618 [11]

Answer:

Step-by-step explanation:

g³ + g² - 12g ≠ 0

g(g² + g - 12) ≠ 0

g(g - 3)(g + 4) ≠ 0

g ≠ 0

g ≠ 3

g ≠ - 4

3 0

3 years ago

If you're starting salary is 40,000 and you receive a 3% increase at the end of every year what is the total amount in dollars y

storchak [24]

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &40000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=\textit{elapsed time}\to &15\\
\end{cases}
\\\\\\
A=40000(1+0.03)^{16}\implies A=40000(1.03)^{16}$

7 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

3 years ago

Help please tell me what the answer is ASAP

Amiraneli [1.4K]

Answer:

The approximated length of EF is 2.2 units ⇒ A

Step-by-step explanation:

<em>The tangent ratio in the right triangle is the ratio between the opposite side to the adjacent side of one of the acute angle in the triangle</em>

In the given figure

∵ The triangle DFE has a right angle F

∵ The opposite side to angle D is EF

∵ The adjacent side to angle D is DF

→ By using the tangent ratio above

∴ tan(∠D) = $\frac{EF}{DF}$

∵ DF = 6 units

∵ m∠D = 20°

→ Substitute then in the ratio above

∴ tan(20°) = $\frac{EF}{6}$

→ Multiply both sides by 6

∴ 6 tan(20°) = EF

∴ 2.183821406 = EF

→ Approximate it to the nearest tenth

∴ 2.2 = EF

∴ The approximated length of EF is 2.2 units

7 0

3 years ago

At the first meeting of the Tennis Club, the 7 members decided to have a tournament in which every player will play a match agai

mariarad [96]

Answer:

21 matches

Step-by-step explanation:

This is a combination problem where we have to select two member out of 7 members

So we want calculation of 7C2

7C2 = 7!/[(2!)(7-2)!]

(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]

(7*6)/2 ~ Note everything that easily cancels here!

42/2

21 matches

5 0

3 years ago