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Alekssandra [29.7K]
3 years ago
7

E. H2CrO4 + Sr(OH)2 →

Chemistry
2 answers:
katrin2010 [14]3 years ago
6 0

Answer:

The answer to your question is SrCrO₄ +  H₂O

Explanation:

Data

  H₂CrO₄  +  Sr(OH)₂  ⇒  

We can notice that this is a Redox reaction or neutralization reaction because the reactants are an acid (H₂CrO₄) and a base (Sr(OH)₂). These reactions are also called double displacement reactions.

In these kind of reactions the products are always a binary or ternary salt and water.

Then, for this reaction,

           H₂CrO₄  +  Sr(OH)₂  ⇒   SrCrO₄ +  H₂O

lilavasa [31]3 years ago
4 0

Answer:

h2Cr4 + 2SrOH

Explanation:

Just so you know the numbers arr represented as little numbers on the side but still are correct. I hope this helps you.

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Calculate the pH of the solution that results when 20 mL of 0.2M HCOOH is mixed with 25mL of 0.2M NaOH solution.(post-equivalenc
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The pH of the solution : 12

<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

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Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

Concentration of [OH⁻] from NaOH :

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pH+pOH=14

pH=14-2=12

3 0
3 years ago
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