This compound should be classified as a suspension fluid. This happens when a fluid is denser than another fluid.
<span>We can solve this problem by assuming that the decay of
cyclopropane follows a 1st order rate of reaction. So that the
equation for decay follows the expression:</span>
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560
M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>
The rate constant should
be given in the problem which I think you forgot to include. For the sake of
calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
<span>Plugging in the values
in the 1st equation:</span>
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 <span>× 10^–4 M (simplify
as necessary)</span>
Answer:
Iodine is a mineral found in some foods. The body must have iodine to make thyroid hormones. The hormones control the body's metabolism and many other important functions. Without iodine, thyroid hormone production can decrease.
Explanation:
Answer:
unless it is acted upon a forcd
Answer:
= 25 %
Explanation:
Given that :
the genotype attributed to trolls having one eye = (EE, Ee); that is homzygous dominant or heterozygote dominant for eye number
Likewise those that posses two eyes have (ee) ; that is homzygous recessive
Now; two heterozygous one eyed trolls are crossed ; we have :
Ee × Ee
The punnet square for this cross looks like what we have below:
E e
E EE Ee
e Ee ee
From the above cross; we have:
1 EE ---- (homozygous dominant ) indicating troll having one eye
2 Ee ---- ( heterozygote dominant ) indicating troll having one eye
1 ee ----- ( homozygous recessive ) indicating troll having two eyes
The genotypic ratio is 1:2:1
Thus; the expected genotype ratio of the two eyed offspring = 
= 25 %
