Answer:
Δ
Explanation:
Hello,
Butane's combustion is:
Now the change in the Gibbs free energy for this reaction is computed via (don't forget that oxygen's Gibbs free energy of formation is 0 since it is an element):
Δ
4Δ
5Δ
-Δ
Δ
Δ
Now, since the calculation is done for 1 mol of butane, the change in the Gibbs free energy for this fuel is:
Δ
Best regards.
Answer:
MECHANISM:
1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.
2) Formation of carbocation.
3) Attack of Nucleophile Br − .
Explanation:
Electrons, everything is pretty much based around the likeliness of electrons to be swapped or shared between atoms
<span>ppm = mg/L
or
Kg solution
Mass % = Mass of Solute/Mass of solution
0.0390 M = x moles/1L
x = 0.0390 Moles of F-
0.0390 mol x 18.998403 g/mol = 0.7409 g
PPM:
1mg = 1000g
0.7409g = 740.9mg
740.9mg/1L = 740.9mg
Mass Percent:
density 1 g/mL
thus
1 g = 1 mL
thus
1 L = 1 kg
thus
1 L = 1000 g
so,
(0.7409 g/1000 g)*100
= 0.07409% (m/m)</span>
