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Mariana [72]
3 years ago
11

Covalent bonds generally form when the bonded elements have a difference in electronegativity less than 1.5. Subtract the electr

onegativities for the following pairs of elements and predict whether they form a covalent bond.
Chemistry
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

The answer to your question is a) Covalent    b) Ionic

Explanation:

Data

Kind of bond between C - C

kind of bond between Mg -Cl

Process

1.- Look for the electronegativities of these elements

Carbon electronegativity = 2.55

Magnesium electronegativity = 1.31

Chlorine electronegativity = 3.16

2.- Calculate the difference of electronegativities

a) C - C = 2.55 - 2.55 = 0          

b) Mg - Cl = 3.16 - 1.31 = 1.85

3.- Kind of bond

a) It's covalent because the difference of electronegativity was lower than

    1.5.

b) It's ionic because the difference of electronegativity was higher than 1.5.  

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6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq)  + 4 \; \text{H}_2 \text{O} \; (l) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s) + 8\; \text{OH}^{-} \; (aq)

<h3>Explanation</h3>
  • The oxidation state of the manganese atom \text{Mn} changes from +7 as in \text{MnO}_4^{-} to +4 as in \text{MnO}_2.
  • There are one \text{Mn} atom in each \text{MnO}_4 ion.
  • Reducing each \text{MnO}_4^{-} ion would thus consume three electrons.
  • Similarly, the oxidation state of the chlorine atom \text{Cl} changes from -1 as in \text{Cl}^{-} to 0 as in \text{Cl}_2.
  • It takes two \text{Cl}^{-} ions to produce one \text{Cl}_2 molecule.
  • Oxidizing every two \text{Cl}^{-} would thus produce one \text{Cl}_2 while releasing two electrons.

Three \text{Cl}_2 molecules contain six chlorine atoms. Three \text{Cl}_2 would thus correspond to six \text{Cl}^{-} ions.

Combining six \text{Cl}^{-}, two \text{MnO}_4^{-} ions, three \text{Cl}_2 ions, and two \text{MnO}_2 would balance the changes in oxidation state.

6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq)  \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s) (NOT BALANCED)

Still, the product side lacks four oxygen atoms.

  • In an acidic environment, oxygen atoms would combine with protons to produce water.
  • In a basic environment (like this one,) there are nearly no protons for oxygen atoms to combine with. Oxygen atoms will likely combine with water to produce hydroxide ions.

Each oxygen atom combine with a water molecule to produce two hydroxide ions. Adding four water molecules and eight hydroxide ions would balance the equation.

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It represents that if the complex compound is dissolved in water it will give a complex ion and the counter ion. The atoms in the bracket cannot break there bonds and will remain un-dissociated.

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