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Nataliya [291]
2 years ago
5

What’s the IUPAC name

Chemistry
1 answer:
hichkok12 [17]2 years ago
5 0

Answer:

Methyl pentanoate.

Explanation:

Hello there!

In this case, according to the given information, we can see the correct structure will be:

                             O

                              ||

CH3CH2CH2CH2COCH3

Which matches with the structure of an ester due to the -COO- functional group. In such a case, the first part of the name is in function of the right side of the ester, in this case, methyl, followed by the left side, pentanoate, as it has five carbon atoms and is an ester (similar to an inorganic salt, but organic) and therefore, the name will be methyl pentanoate.

Regards!

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Enter a balanced equation for the complete combustion of liquid C3H7OH. Express your answer as a chemical equation. Identify all
Vlad1618 [11]

2 C₃H₇OH (l) +  9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)

Explanation:

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Bellow we have the balanced chemical equation of the complete combustion of C₃H₇OH:

C₃H₇OH (l) +  (9/2) O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)

to have integer coefficients  we multiply the reaction with 2:

2 C₃H₇OH (l) +  9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)

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3 years ago
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
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Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

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