You would know that the variable is quantitative if it shows any number to express the quantity. For example, quantitative variables are 50°C, 5 atm, 2 moles, 100 L and so on. A variable is qualitative if it expresses a relative quantity but not expressing a number. Examples would be: few, too hot, several, or even describing the characteristics of a variable. Hence, when the variable is in grams, then that would be quantitative.
Answer:
3.676 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have different values of V and T:
(V₁T₂) = (V₂T₁)
V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,
V₂ = ??? L, T₂ = 40°C + 273 = 313 K,
- Applying in the above equation
(V₁T₂) = (V₂T₁)
∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.
Answer:
Tea is a solution of compounds in water, so it is not chemically pure.
Explanation:
It is usually separated from tea leaves by filtration. B Because the composition of the solution is uniform throughout, it is a homogeneous mixture.
Answer:
Its electron configuration is: 2 electrons in the K shell (principal quantum number 1), 8 in the L shell (principal quantum number 2), 8 in the M shell (principal quantum number 3), and 2 in the N shell (principal quantum number 4).
Explanation:
Hope this helped!!! xoxo
t!kt0k: preppydreams
Answer:
0.272 mol
Explanation:
∆Tb = m × Kb
∆Tb = 85.2°C - 78.4°C = 6.8°C
Kb = 1.22°C/m
mass of ethanol = 48.80 g = 48.80/1000 = 0.0488 kg
Let the moles of non-ionizing solute be y
m (molality) = y/0.0488
6.8 = y/0.0488 × 1.22
y = 6.8×0.0488/1.22 = 0.272 mol
