Enter the correct 4 digit code (no spaces)

the absolute tempeature of a gas is increased four times while maintaining a constant volume. what happens to the pressure of th

ikadub [295]

Answer:

increases

Explanation:

6 0

3 years ago

What are the Group 1A and Group 7A elements examples of?

Scrat [10]

Alkali metals = Group 1A
Halogens = Group 7A

6 0

4 years ago

Read 2 more answers

Determine the theoretical yield of P2O5, when 3.07 g of P reacts with 6.09 g of oxygen in the following chemical equation

saveliy_v [14]

Answer: 14.2 grams

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

given mass of phosphorous (P) = 3.07 g

Molar mass of phosphorous (P) = 31 g/mol

Putting in the values we get:

$\text{Number of moles of phosphorous}=\frac{3.07g}{31g/mol}=0.1moles$

given mass of oxygen $O_2$ = 6.09 g

Molar mass of oxygen $O_2$ = 32 g/mol

Putting in the values we get:

$\text{Number of moles of oxygen}=\frac{6.09g}{32g/mol}=0.2moles$

According to stoichiometry:

$4P+5O_2\rightarrow 2P_2O_5$

4 moles of phosphorous combine with 5 moles of oxygen

Thus 0.1 moles of phosphorous combine with = $\frac{5}{4}\times 0.1=0.125$ moles of oxygen

Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.

4 moles of phosphorous gives= 2 moles of $P_2O_5$

Thus 0.1 moles of phosphorous gives = $\frac{2}{4}\times 0.1=0.05$ moles of $P_2O_5$

mass of $P_2O_5=moles\times {\text {Molar mass}}=0.05\times 284=14.2g$

Thus the theoretical yield of $P_2O_5$ is 14.2 grams.

5 0

3 years ago

A chemist prepares a solution of copper(II) fluoride (CuF2) by measuring out 0.032 µmol of copper(II) fluoride into a 500 mL vol

schepotkina [342]

Answer : The concentration of copper(II) fluoride in the solution is, $6.4\times 10^{-8}mole/L$

Explanation : Given,

Moles of copper(II) fluoride = 0.032 μ

mol = $0.032\times 10^{-6}mol=3.2\times 10^{-8}mol$

conversion used : $\mu mol=10^{-6}mol$

Volume of solution = 500 mL

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of copper(II) fluoride}\times 1000}{\text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{3.2\times 10^{-8}mol\times 1000}{500mL}=6.4\times 10^{-8}mole/L$

Therefore, the concentration of copper(II) fluoride in the solution is, $6.4\times 10^{-8}mole/L$

4 0

3 years ago

A rectangular container of air measures 1.2 x 10-2 m by 8.34 x 10 1 m by 6.0 x 10-1 m. Air

Dominik [7]

The volume of the rectangle has been given by the product of length, breadth, and height. The mass of the air with a density of 1180 g/m³ is 708.57 gms.

<h3>What is density?</h3>

The density of the substance has been known to be given by the mass's ratio to the volume. The formula for density is given as,

Density = Mass ÷ Volume

Given,

Density = 1180 g/m³

The volume of the rectangle = L×B×H

Substituting the values above,

Mass = Density × Volume

M = 1180 × 1.2 × 10⁻² × 8.34 × 10¹ × 6.0 × 10⁻¹

= 708.57 gm

Therefore, the mass of the air is 708.57 gms.

Learn more about density here:

brainly.com/question/952755

#SPJ1

8 0

2 years ago