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4 years ago

I realllllly need help thankyou

Mathematics

1 answer:

Minchanka [31]4 years ago

7 0

Square root of 30=5.5
square root of 35=5.9
square root of 40=6.3
square root of 45=6.7
square root of 50=7

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(06.04 MC)What is the volume of four cubes with a side length of fraction 1 over 4 foot? V = s3, where s is the side length.

PIT_PIT [208]

Volume of 1 cube = s^3

s= side

so, vol = (1/4)^3 = 1 / 64

Now, there are 4 cubes:
So, volume of 4 cubes = (1 / 64 ) x 4 = 1 /16

Unit will obviously be foot^3

7 0

3 years ago

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A helicopter floats 120m above a helipad, a dog is 85m from the helipad, if the dog could fly, how far would it have to fly to g

suter [353]

If the dog could fly, it would need to fly 147 meters to catch the helicopter

This is a rather easy and straightforward question. We are going to solve it using Pythagoras theorem. We can interpret the question to be in a triangle where the height of the helicopter above the helipad and away from the dog is the right angle. This also means that the distance needed, between the dog and the helicopter is the hypotenuse.

Using pythagoras theorem, we have

120² + 85² = c²

c² = 14400 + 7225

c² = 21625

c = $\sqrt{21625}$

c = ±147 meters.

Since distance cant be in the negative, our answer is 147 m

read more about pythagoras theorem here brainly.com/question/15138986

3 0

3 years ago

Michelle used a scale to measure to rocks. One rock weighs 7/10 pound. The other rock weighs 25/100 pounds. What fraction repres

Mnenie [13.5K]

25/100 + 7/10 = 0.95

5 0

3 years ago

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Someone please help and explain if you can. I'm not sure what I'm supposed to do :/ (Will give brainiest if correct, if possible

Stella [2.4K]

The first one s=square root of 99 in.

4 0

3 years ago

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PLEASE PLEASE HELP ME OUT ITS URGENT What are the solutions to the quadratic equation?

mixer [17]

Answer: Choice C) $x = 4\pm2\sqrt{10}$

This is the same as saying $x = 4+2\sqrt{10} \ \ \text{ or } \ \ x = 4-2\sqrt{10}$

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Explanation:

First get everything to one side

x^2 + 13 = 8x + 37

x^2 + 13 - 8x - 37 = 0

x^2 - 8x - 24 = 0

Here we have a quadratic in the form ax^2+bx+c = 0

Note how a = 1, b = -8, c = -24

Those values are plugged into the quadratic formula below

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-8)\pm\sqrt{(-8)^2-4(1)(-24)}}{2(1)}\\\\x = \frac{8\pm\sqrt{160}}{2}\\\\x = \frac{8\pm\sqrt{16*10}}{2}\\\\x = \frac{8\pm\sqrt{16}*\sqrt{10}}{2}\\\\x = \frac{8\pm4*\sqrt{10}}{2}\\\\x = \frac{2(4\pm2\sqrt{10})}{2}\\\\x = 4\pm2\sqrt{10}$

This shows the answer is choice C.

The plus minus breaks down that equation these two solutions

$x = 4+2\sqrt{10} \ \ \text{ or } \ \ x = 4-2\sqrt{10}$

6 0

3 years ago

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