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erica [24]
3 years ago
13

Astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is toda

y. When astronomers make such a statement, how can they know what was happening inside galaxies way back then
Physics
1 answer:
disa [49]3 years ago
8 0

Answer:

First, as you may know, the light travels at a given velocity.

In vaccum, this velocity is c = 3x10^8 m/s.

And we know that:

distance = velocity*time

Now, if some object (like a star ) is really far away, the light that comes from that star may take years to reach the Earth.

This means that the images that the astronomers see today, actually happened years and years ago (So the night sky is like a picture of the "past" of the universe)

Also, for example, if an astronomer sees some particular thing, he can apply a model (a "simplification" of some phenomena that is used to simplify it an explain it) and with the model, the scientist can infer the information of the given thing some time before it was seen.

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A boat is moving due east in a region where the earth's magnetic field is 5.0×10⁻⁵ NA⁻¹ m⁻¹ due north and horizontal. The boat c
sesenic [268]

Answer: Induced emf is given by:

ε= Bvl

On putting the values we get

=5×10

−5

×1.50×2

=0.15mV

Explanation:

Hope these helped have a wonderful Christmas break ❄️

7 0
3 years ago
Scientists in the laboratory create a uniform electric field e⃗ = 6. 0×105 k^v/m in a region of space where b⃗ =0⃗
zvonat [6]

Scientist in the laboratory create uniform electric field.

PART A: The electric field in rocket frame is  (0,0,  6.0 × 10 ⁵).

PART B: The magnetic field in the rocket frame is  7.3 × 10⁻⁶ j∧  .

<h3>What is uniform electric field?</h3>

The electric field whose strength is not changing with respect to time is called uniform magnetic field.

The electric field is 6.0 × 10 ⁵ k^v/m and the magnetic field is zero.

E' = E + (V×B)

    = 6.0 × 10 ⁵ + (1.1 × 10⁶ × 0)

E' = 6.0 × 10 ⁵ k∧

(Ex , Ey, Ez) = (0,0,  6.0 × 10 ⁵)

The new magnetic field is represented as

B' = B - 1 /c²(v × E)

   =0 - 1 / (3× 10⁸)²(1.1 × 10⁶ i∧ × 6.0 × 10 ⁵k∧ )

B' = 7.3 × 10⁻⁶ j∧

PART A: The electric field in rocket frame is  (0,0,  6.0 × 10 ⁵).

PART B: The magnetic field in the rocket frame is 7.3 × 10⁻⁶ j∧ .

Learn more about uniform electric field.

brainly.com/question/26446532

#SPJ4

7 0
2 years ago
6. Which is a characteristic of the observant function?
nlexa [21]

Focusing on the present is a characteristic of the observant function.

<h3>What is an Observant personality trait?</h3>

This trait is characterized by people who pay much attention to themselves more than others.

This type of people focus on the present and ensure things are done without procrastination. This depicts the option D which makes it the most appropriate choice.

Read more about Observant trait here brainly.com/question/12283441

7 0
2 years ago
PLEASE HELP WILL MARK BRAINLIST
Alex17521 [72]

Answer: Both A and B

Explanation:

The objects are in contact so it would depend on the amount of force that is pressing them as to the amount of friction and it would depend on the smoothness as too the amount of friction that is added

6 0
3 years ago
A block of mass M on a horizontal surface is connected to the end of a massless spring of spring constant k. The block is pulled
slamgirl [31]

Answer:

Minimum coefficient of kinetic friction between the surface and the block is \mu_k=\frac{kx}{2Mg} .

Explanation:

Given:

Mass of the block = M

Spring constant = k

Distance pulled = x

According to the question:

<em>We have to find the minimum co-efficient of kinetic friction between the surface and the block that will prevent the block from returning to its equilibrium with non-zero speed.  </em>

So,

From the FBD we can say that:

⇒ Normal force, N=Mg                                   <em>...equation(i)</em>

⇒ Elastic potential energy, PE = \frac{kx^2}{2}               <em>  ...equation (ii)</em>

⇒ Frictional force, f = \mu_kN                                <em> ...equation (iii)</em>

⇒ Plugging (i) in (iii).

⇒ f=\mu_kMg

Now,

⇒ As we know that the energy lost due to friction is equivalent to PE .

⇒ PE=fx                     <em>...considering PE as</em> mgh or f(x) .

   Arranging the equation.

⇒ \frac{kx^2}{2}=\mu_k Mg (x)

⇒ \frac{kx}{2}=\mu_k Mg                 <em>...eliminating x from both sides.</em>

⇒ \frac{kx}{2Mg}=\mu_k                    <em>...dividing both sides wit Mg.</em>

Minimum coefficient of kinetic friction between the surface and the block is \frac{kx}{2Mg}=\mu_k .

4 0
4 years ago
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