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Doss [256]
2 years ago
12

State Newton's first law of motion.​

Physics
2 answers:
Anika [276]2 years ago
5 0

Answer:

<em>Newton</em><em> </em><em>'</em><em>s</em><em> </em><em>First</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>motion</em><em> </em><em>States</em><em> </em><em>that</em><em> </em><em><u> a body at rest will remain at rest position only and a body which is in motion continues to be in motion </u></em><em><u>until</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>unless</u></em><em><u> </u></em><em><u>any</u></em><em><u> </u></em><em><u>external</u></em><em><u> </u></em><em><u>Force</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>applied</u></em><em><u>.</u></em><em><u> </u></em>

Explanation:

Hope it helps!.

bonufazy [111]2 years ago
5 0

Answer:

Newton's first law states that if a body is at rest it will remain at rest and if a body is in motion it will remain in motion until an external force is applied on the body.

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3 years ago
A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the
sp2606 [1]
From the question,
u = 0m {s}^{ - 1}
v = 6m {s}^{ - 1}

t = 3s
F=12N



Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.

Ft =m(v-u)


12(3.0)=m(6.0- \: 0)
This implies that

36.0 = 6m
m =  \frac{36.0}{6.0}
\therefore \: m = 6.0kg


You can also use the equation of linear motion,
v = u + at
6 = 0 + a(3)
6 = 3a
a =  \frac{6}{3}

a = 2 {ms}^{ - 2}
But
F=ma
12 = m(2)
12 = 2m
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\therefore \: m = 6kg
4 0
3 years ago
How does radioactive decay work
Lesechka [4]

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Explanation:

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Answer:

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Explanation:

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