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Doss [256]
2 years ago
12

State Newton's first law of motion.​

Physics
2 answers:
Anika [276]2 years ago
5 0

Answer:

<em>Newton</em><em> </em><em>'</em><em>s</em><em> </em><em>First</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>motion</em><em> </em><em>States</em><em> </em><em>that</em><em> </em><em><u> a body at rest will remain at rest position only and a body which is in motion continues to be in motion </u></em><em><u>until</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>unless</u></em><em><u> </u></em><em><u>any</u></em><em><u> </u></em><em><u>external</u></em><em><u> </u></em><em><u>Force</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>applied</u></em><em><u>.</u></em><em><u> </u></em>

Explanation:

Hope it helps!.

bonufazy [111]2 years ago
5 0

Answer:

Newton's first law states that if a body is at rest it will remain at rest and if a body is in motion it will remain in motion until an external force is applied on the body.

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aleksandr82 [10.1K]
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Que unidad de medida se utiliza para expresar la capacidad o volumen de un objeto? Da un ejemplo
galina1969 [7]

Answer:

<em>Explicado a continuación</em>

Explanation:

Hay una pequeña diferencia conceptual entre la capacidad y el volumen de un objeto, a saber:

El volumen hace referencia al espacio que ocupa un objeto, mientras que la capacidad hace referencia al espacio que este contiene. Calcular el volumen de un cuerpo es medir cuánto ocupa mientras que calcular su capacidad es medir cuánto cabe en él.

En la práctica, ambos conceptos son usados indistintamente, ya que tienen unidades equivalentes.

El volumen tiene unidades de longitud al cubo, como por ejemplo:

m^3,\ cm^3\ ,dm^3,\ pie^3\ , pulg^3

y la capacidad se suele expresar en litros o unidades derivadas: litro, mililitro, centilitro, etc.

Como mencionamos, hay equivalencia engre los dos grupos de unidades. Entre las más conocidas están:

1\ lt=1\ dm^3,\ 1\ m^3=1000\ lt

5 0
2 years ago
An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq
Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, f_2 = 1227 Hz

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

f_2=\dfrac{3v}{2l}

v is speed of sound

Let f is the fundamental frequency. It is given by :

f=\dfrac{v}{2l}

The relation between f and f₂ can be written as :

f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz

So, the fundamental frequency of the pipe is 409 Hz.              

6 0
2 years ago
An 8 Ω resistor is connected to a 6 V battery and another resistor in series. If the current in the circuit is 0.5 A, what is th
Semmy [17]
8+R=V/I
8+R=6/0.5=12 ohm
then R=4 ohm
4 0
2 years ago
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