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ICE Princess25 [194]
3 years ago
9

To provide the pulse of energy needed for an intense bass, some car stereo systems add capacitors. One system uses a 1.6FF capac

itor charged to 24 VV, double the normal 12 VV provided by the car's battery. How much energy does the capacitor store at 12 V? How much energy does the capacitor store at 24 V?
Physics
2 answers:
AleksandrR [38]3 years ago
7 0

Answer:

Explanation:

Capacitance, C = 1.6 F

(a) V = 12 V

Energy stored in a capacitor,

U = 0.5 C V²

U = 0.5 x 1.6 x 12 x 12 = 115.2 J

(b) V = 24 V

Energy stored in a capacitor,

U = 0.5 C V²

U = 0.5 x 1.6 x 24 x 24 = 460.8 J

Hoochie [10]3 years ago
6 0

Answer:

Energy stored at 12 volt will be 115.2 J and energy stored at 24 volt will be 460.8 volt

Explanation:

We have given capacitance of capacitor C = 1.6 F

Normal voltage V = 12 volt

And system uses 2 volt to charge the system

We know that energy stored in the capacitor is equal to E=\frac{1}{2}CV^2

So energy stored at 12 volt will be equal to E=\frac{1}{2}\times 1.6\times 12^2=115.2j

And energy stored at 24 volt will be equal to E=\frac{1}{2}\times 1.6\times 24^2=460.8j

So energy stored at 12 volt will be 115.2 j and energy stored at 24 volt will be 460.8 j

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Answer: vf1/vf2= 1/ sqrt(2)

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when the rock reach the bottom y=H so:

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The mandible in the bone that allows you to open and close your mouth, otherwise known ad the jawbone.

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3 years ago
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A stone was dropped off a cliff and hit the ground with a speed of 88 ft/s. What is the height (in feet) of the cliff
igor_vitrenko [27]

Answer:

the height (in feet) of the cliff is 121 ft

Explanation:

A stone hit the cliff with

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height is h.

To solve this problem we will apply the linear motion kinematic equations, Equation of motion describes change in velocity, depending on the acceleration and the distance traveled

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h=(88)^2 / 64

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the height (in feet) of the cliff is 121 ft

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Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
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Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

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optical path difference for bright fringe is given as=n\lambda

Here,

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