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3 years ago

K divided by 11 is 7

2 answers:

5 0

K/11 = 7
multiply 11 to both sides
K/11 (11) = 7(11)
multiply 7 and eleven together
K = 7(11)
Answer
K = 77

77 is your answer

hope this helps

attashe74 [19]3 years ago

3 0

K/11=7

Then multiplying by 11 from the both sides.

11K/11=7·11

Finally to simplifying 7 times 11 and cross out the 11 and please do not cross out the k letter.

Answer is K=77.

It will help you.

-Charlie

Have a great day!!!!!!!!!

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The length of a Train A is 480 m and it takes 2 minutes to cross a tunnel of length 1,320 m. The length of a Train B, which is s

nasty-shy [4]

Answer: 52.94

Step-by-step explanation:

Length of train A = 480m

Tunnel length = 1320m

Time taken to cross tunnel = 2 mins = 120sec

Length of train B = 420m

Train B is slower than train A

Difference between their speed = 18km/hr

18km/hr = (18×1000)/3600 = 5m/s

Speed of train A :

Speed = distance / time

Speed = 1320 / 120 = 11m/s

Therefore, speed of train B :

(11 - 5)m/s = 6m/s

Relative speed of the two trains is therefore;

(Speed of A + speed of B)

Note : they are moving in opposite direction

( 11 + 6)m/s = 17m/s

Therefore time taken to cross each other :

(Sum of the length of both trains / relative speed of the trains)

Time taken = (480m + 420m) / (17m/s)

Time taken = 900m / 17m/s

Time taken = 52.94s

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2 years ago

The record low temp in Fargo, ND is -37*F. The record high is 109*F. What is the difference in the record high and the record lo

yuradex [85]

Answer:

109 - -37 = 146

Step-by-step explanation:

since you are subtracting a negative, the negative number and the sign cancel each other out. So all you have to do is add.

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1 year ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago

Identify the initial amount a and the growth or decay factor b in the exponential function. y = 0.01025^x

Nastasia [14]

Answer:

The initial amount a = 1

The growth or decay factor = 0.01025

Step-by-step explanation:

The exponential function.

y = 0.01025^x

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The exponential equation can be rewritten as Y = 1(0.01025)^x

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2 years ago

Well... I think you get the point

Mariana [72]

Answer:

Choice B

Step-by-step explanation:

USE PEMDAS

First do the things in the parenthesis. 2 1/3- 3/4 is 19/12

Multiply 19/12 by 1/6. You get 19/72. Add 5/24. You get 34/72. Simplify: 17/36

Please give my Brainliest I would really appreciate it!

Hope this helps!

8 0

2 years ago