Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
The supplement of < 72 has the same measure as < (4x + 8). Therefore, < (4x + 8) must equal 108°. We can establish the following equality statement to solve for x:
< (4x + 8) + < 72° = 180°
Combine like terms:
4x + 80 = 180°
Subtract 80 from both sides:
4x + 80° - 80° = 180° - 80°
4x = 100
Divide both sides by 4 to solve for x:
4x/4 = 100/4
x = 25
To verify whether the value of x is correct, substitute its value into the equality statement:
< (4x + 8)° + < 72° = 180°
< [4(25) + 8]° + < 72° = 180°
< (100 + 8)° + < 72° = 180°
< 108° + < 72° = 180°
180° = 180° (True statement. Therefore, the correct answer is x = 25).
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Answer: Equation: E= 20H
Earning's after 15 hours: E= 20(15)
E = 300
Step-by-step explanation:
The equation would be E =20H. E means her total earnings. 20 is how much money she earns per hour. H is how many hours she tutors. If you put it all together, you get E = 20H.
To solve how much she would get for 15 hours, plug in 15 for H so E=20(15). 20 x 15 = 300. Therefore, she will get $300 after teaching for 15 hours.
Answer:
Yes
Step-by-step explanation:
If you divide all the sides of the larger triangle by 3, it's equivalent to the sides of the smaller triangle. Therefore, they are similar.
