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3 years ago

Before the positive psychology movement, psychology focused mainly on

2 answers:

7 0

Before positive psychology, the main focus was mostly pathology, that is, studying various psychological issues and sometimes finding ways to treat them, or sometimes not and just studying them for the sake of studying them and noting their occurrence.

MArishka [77]3 years ago

3 0

Answer choices are:

A) personality style upbringing

B) positive thoughts and feelings of people

C) negative and dysfunctional aspects of emotions and behavior

D) the history of mental illness.

____________________________________________________________

Correct answer choice is:

D) The history of mental illness.

____________________________________________________________

Explanation:

Mental health is a stage of emotional well-being or an inadequacy of mental illness. It is the "mental state of someone who is performing at a competent level of nervous and behavioral change".

The philosopher and physician, Hippocrates, found that illnesses develop from “natural happenings in the body” (Foerschner). As Hippocrates was inquiring about subjective illness, he passed away from the erroneous assumptions and towards the therapeutic aspect of it.

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Mark creates a graphic organizer to review his notes about electrical force. Which labels belong in the regions marked X and Y?

sveta [45]

Answer:

The correct answer is A

Explanation:

The question requires as well the attached image, so please see that below.

Coulomb's Law.

The electrical force can be understood by remembering Coulomb's Law, that describes the electrostatic force between two charged particles. If the particles have charges $q_1$ and $q_2$ , are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

$|F|=k \cfrac{q_1 q_2}{r^2}$

Thus if we decrease the distance by half we have

$r_1 =\cfrac r2$

So we get

$|F|=k \cfrac{q_1 q_2}{r_1^2}$

Replacing we get

$|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}$

We can then multiply both numerator and denominator by 4 to get

$|F|=k \cfrac{4q_1 q_2}{r^2}$

So we have

$|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)$

Thus if we decrease the distance by half we get four times the force.

Then we can replace the second condition

$q_{2new} =2q_2$

So we get

$|F|=k \cfrac{q_1 q_{2new}}{r_1^2}$

which give us

$|F|=k \cfrac{q_1 2q_2}{r_1^2}\\|F|=2\left(k \cfrac{q_1 q_2}{r_1^2}\right)$

Thus doubling one of the charges doubles the force.

So the answer is A.

8 0

3 years ago

Read 2 more answers

Which describes refraction? *

sergey [27]

Answer:

Refracted rays travel through a boundary into a new medium.

Explanation:

Refracted rays travel through a boundary into a new medium. is only true for refraction.

The angle of incidence is the same for angle of refraction, is not true for refraction. Refraction follows Snell's law, states that ratio of the sine of the angle of refraction and the sine of the angle of incidence is always constant and equivalent to the ratio of phase velocities of the two mediums it is passing through.

Refracted rays change direction and go back to the original medium is false for refraction however, it is true for reflection.

5 0

3 years ago

Which statement most accurately finishes the sentence: force always ... 1. Come in pairs

lys-0071 [83]

Comes in pairs
Just like in Newton’s 3rd law, there is always an equal and opposite force

6 0

3 years ago

A 900-kg car cruising at a constant speed of 60 km/h is to accelerate to 100 km/h in 4 s. The additional power needed to achieve

kiruha [24]

To solve this problem we will apply the concepts related to power as a function of the change of energy with respect to time. But we will consider the energy in the body equivalent to kinetic energy. The change in said energy will be the difference between the two velocity data given by half of the mass. We will first convert the given units into an international system like this

Initial Velocity,

$V_i = 60km/h (\frac{1000m}{1km})(\frac{1h}{3600s})$