Answer:
![t=45.7s](https://tex.z-dn.net/?f=t%3D45.7s)
![\alpha =116revolutions](https://tex.z-dn.net/?f=%5Calpha%20%3D116revolutions)
Explanation:
Since we have given values of ω₀=32.o rad/s ,ω=0 and α=-0.700 rad/s² to find t we use below equation
![w=w_{o}+at\\ 0=(32.0rad/s)+(-0.700rad/s^{2} )t\\t=\frac{-32.0}{-0.700} \\t=45.7s](https://tex.z-dn.net/?f=w%3Dw_%7Bo%7D%2Bat%5C%5C%20%200%3D%2832.0rad%2Fs%29%2B%28-0.700rad%2Fs%5E%7B2%7D%20%29t%5C%5Ct%3D%5Cfrac%7B-32.0%7D%7B-0.700%7D%20%5C%5Ct%3D45.7s)
To find revolutions we use below equation
![w^{2}=w_{o}^{2}+2a\alpha](https://tex.z-dn.net/?f=w%5E%7B2%7D%3Dw_%7Bo%7D%5E%7B2%7D%2B2a%5Calpha)
Substitute the given values to find revolutions α
So
![0=(32.0rad/s)^{2}+2(-0.700rad/s^{2} )\alpha \\\alpha =\frac{(-32.0rad/s)^{2}}{2(-0.700rad/s^{2} )} \\\alpha =731rad](https://tex.z-dn.net/?f=0%3D%2832.0rad%2Fs%29%5E%7B2%7D%2B2%28-0.700rad%2Fs%5E%7B2%7D%20%29%5Calpha%20%20%5C%5C%5Calpha%20%3D%5Cfrac%7B%28-32.0rad%2Fs%29%5E%7B2%7D%7D%7B2%28-0.700rad%2Fs%5E%7B2%7D%20%29%7D%20%5C%5C%5Calpha%20%3D731rad)
To convert rad to rev:
![\alpha =(731rad)*(\frac{1rev}{2\pi rad} )\\\alpha =116revolutions](https://tex.z-dn.net/?f=%5Calpha%20%3D%28731rad%29%2A%28%5Cfrac%7B1rev%7D%7B2%5Cpi%20rad%7D%20%29%5C%5C%5Calpha%20%3D116revolutions)
Answer:
4.54
Explanation:
X+10X=50
11X=50
X=4.54#
<h2>please follow me...</h2>
An isotonic solution is <span>a solution in which concentration or solute is equal to that of a cell placed in it. Thus, the system is in dynamic equilibrium, and so water molecules flow in both directions.
The correct answer is <u>C. w</u></span><span><u>ater molecules flow in both directions at the same rate.</u></span>
It can't. Waves must have a medium to travel through
Answer:
Er = 108 [J]
Explanation:
To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.
200 - 44 - 48 = Er
Where:
Er = remaining energy [J]
Er = 108 [J]