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Helen [10]
3 years ago
10

A 5-kg can of paint is sitting on top of a 2-meter high step ladder. How much work did you do to move the can of paint to the to

p of the ladder? What is the potential energy of the can of paint?
Physics
1 answer:
Xelga [282]3 years ago
3 0

98J

Explanation:

Given parameters:

Mass of paint can = 5kg

Height of ladder = 2m

Unknown:

Work done = ?

Potential energy = ?

Solution:

Work done in moving the paint is the force applied under gravity to move it through the give height.

Potential energy is the energy due the position of a body at rest.

For this body:

The work done in moving the paint =  Potential energy at the top of ladder = m x  g x h

m is the mass of the pain can

g is the acceleration due to gravity

h is the height of the building

Input the variables;

 Work done = 5 x 9.8 x 2 = 98J

Potential energy  = 98J

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

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a line passes through (8,-4) and has a slope 2/3. what is an equation in point slope form of the line? An equation of the line i
evablogger [386]

from the question

x₁ = x-coordinate = 8

y₁ = y-coordinate = - 4

m = slope of line = 2/3

slope form of the line is given as

(y - y₁ ) = m (x - x₁)

inserting the values

(y - (- 4) ) = (2/3) (x - 8)

(3) (y + 4) = (2) (x - 8)

multiplying each term inside the bracket by 3  and 2 respective on left and right side

3y + 12 = 2 x - 16

2 x - 3 y - 16 - 12 = 0

2 x - 3 y - 28 = 0




7 0
3 years ago
A 22.0 kg child slides down a slide that makes a 37.0° angle with the horizontal. (a) What is the magnitude of the normal force
patriot [66]

Answer:

(a) 172.185 N

(b) 53^{\circ}

Solution:

As per the question:

Mass of the child, m = 22.0 kg

Angle, \theta = 37.0^{\circ}

Now,

(a) The magnitude of the normal force exerted by the slide on the child:

F_{N} = mgcos\theta

F_{N} = 22\times 9.8cos37^{\circ} = 172.185\ N

Now,

(b) The angle from the horizontal at which the force is directed is:

90^{\circ} - 37^{\circ} = 53^{\circ}

6 0
3 years ago
A rocket is fired at a 45° angle, what is the direction of the horizontal velocity vector at the peak height?
Bess [88]

Answer:

B: Horizontally to the left

Explanation:

Horizontal velocity is always constant throughout the entire trajectory of the rocket and acts in the horizontal direction in which the rocket was launched. This is because gravity only acts in the downwards vertical direction.

So in order words at peak height, horizontal velocity is in the horizontal direction in which the rocket was launched.

So if it was to the left, then direction is left but if right, then direction is right.

Looking at the options, the most appropriate will be:

Horizontally to the left

7 0
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A doctor has a patient blow on one side of a U-shaped tube that is partially
mart [117]

Answer:

A. 150 Pa

Explanation:

Answer is 150 Pa

8 0
3 years ago
How do line symmetry differ from rotational symmetry?.
sergeinik [125]

Answer:

A line of symmetry is a line that separates a shape into two identical halves.
Rotational symmetry is the same thing except when you rotate the object, it has to have the exact same line of symmetry.

<u><em>Hope this helps!!!</em></u>

3 0
2 years ago
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