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likoan [24]
3 years ago
14

Consider the elastic head-on collision between a sledge hammer with 2000 g mass and a golf ball with a 5 g mass. The initial vel

ocity of the sledge hammer is 16 m/s, and the golf ball is initially at rest.
Physics
1 answer:
alexandr402 [8]3 years ago
4 0

Answer:

v2=6400m/s

Explanation:

Consider the elastic head-on collision between a sledge hammer with 2000 g mass and a golf ball with a 5 g mass. The initial velocity of the sledge hammer is 16 m/s, and the golf ball is initially at rest. the concluding part of this question could be:

this is an elastic collision

we know from the principles of linear momentum that the total momentum before collision must be equal to total linear momentum after collision

momentum is the product of mass and its velocity

m1u1+m2u2=m1v1+m2v2

m1=2000g mass of the sledge hammer

u1=16m/s initial velocity of the sledge hammer

m2=5g mass of the golf ball

u2=0 velocity of the golf ball

v1=0m/s final velocity of the sledge hammer

v2=? final velocity of the golf ball

2000*16+5*0=2000*0+5v2

v2=2000*16/5

v2=400*16

v2=6400 m/s

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Answer:

<em>The age of the universe would be larger.</em>

Explanation:

The Hubble relation states that an astronomical object's velocity is proportional to the distance between the observer and the object.

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where

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If the Hubble constant decreases, the velocity will decrease.

Time is determined by taking the quotient between the distance and the velocity.

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you slide abox of books at constant speed up a30 degree ramp, applying a force of 200 newtons directed up the slope. The coeffic
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The work done is 400 J

Explanation:

The work done by you in pushing the box along the slope is given by

W=Fd

where

F is the magnitude of the force applied

d is the distance covered by the box along the slope

Here we have the following:

F = 200 N is the magnitude of the force applied

d=\frac{h}{sin \theta} is the distance covered, where

h = 1 m is the vertical rise

\theta=30^{\circ} is the slope of the plane

Substituting and solving, we find

W=F\frac{h}{sin \theta}=\frac{(200)(1)}{sin 30^{\circ}}=400 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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Answer:

Convection and Radiation mechanisms carry most of the heat

Explanation:

This is because Convection proceeds strongy as heated air rises from the hot element while Radiation is also strong, although the material of the cooking pots will how effective it is.

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Answer:

Explanation:

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