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Ber [7]
2 years ago
10

Graphs and lines. please help thx

Mathematics
1 answer:
Elodia [21]2 years ago
3 0

Answer:

y=\frac{4}{3}x+4

Step-by-step explanation:

In order to identify the equation of line from the given graph, we need to find the slope and the y-intercept.

Slope of a line is the ratio of rise to run or change in y over change in x.

The y-intercept is a point on the line for which the x value is 0. In other words, it is on the y-axis.

Here, from the graph,

y-intercept is at point (0,4). So, y-intercept is the y value which is,b= 4.

Also, slope is given as, m=\frac{\Delta y}{\Delta x}=\frac{4}{3}

Therefore, the equation of the line is:

y=mx+b\\y=\frac{4}{3}x+4

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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
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1.92/8 = .24 and more stuff like that.

7 0
3 years ago
Next, find the length of BC. Place point F at (4,4), and draw BF and FC. Find BF and FC using the coordinates of B, C, and F. Th
hammer [34]

9514 1404 393

Answer:

  BC = 5

Step-by-step explanation:

Of course, this geometry program can tell you the length of BC.

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If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...

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7 0
2 years ago
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That is how u would do it

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Answer:

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