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Anton [14]
3 years ago
9

How many moles are in 88.1 of magnesium

Chemistry
1 answer:
valkas [14]3 years ago
7 0
For this you need the atomic mass of Mg. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. 

88.1 moles Mg × 24.3 grams = 2140.83 moles Mg
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adam wants to investigate the strengths of different acids and alkalis. He has 2 different acid solutions and 2 different alkali
SCORPION-xisa [38]

Answer:

The strength of an acid or alkali depends on the degree of dissociation of the acid or alkali in water. The degree of dissociation measures the percentage of acid molecules that ionise when dissolved in water. He could use universal indicators or litmus paper for this.

Explanation:

(See answer for the explanation)

5 0
3 years ago
If an atom of chlorine had an atomic mass of 17 and it gained an electron what would you have?
Sonbull [250]
The atomic mass would not change since the mass of an electron is negligible compared to the mass of protons and neutrons
4 0
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Which of the following is true for balancing equations?
algol [13]

Answer:

A.

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

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5 0
3 years ago
Assuming 1 mol of Fe3+ and 2 mol of SCN- were allowed to react and reach equilibrium. 0.5 mol of product was formed. The total v
zaharov [31]

Answer:

a. 0.5 mol

b. 1.5 mol

c. 0.67

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b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium

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3 0
3 years ago
How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

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mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
3 years ago
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