The hint in this problem is in the word "about" or
approximately how many pounds.
So we could find the solution by estimation through rounding
off.
We know that almonds cost about 3.50 per pound and
a bag costs about $7.00.
Dividing 7 by 3.50 per pound, will give us $7 ÷ $3.50 = 2
pounds.
The answer is 2 pounds.
According to research, none of these men were executed for believing that Earth revolves around the sun. Nicolaus Copernicus was the first to believe in the heliocentric view of the current solar system, but he was not killed for that view, but he died of natural means. Galileo Galilei was punished because of the heliocentric view but was only put under house arrest, and not killed. Giordano Bruno was indeed burned at stake, but it was not for his view on heliocentrism.
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(1,152 BTU) x (1,055.06 joule/BTU)=<span>1,215,429.12</span>
I Hope This Helps Dear! :D
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Answer:
Smaller velocity from the bigger one
Explanation:
When one calculates velocity they subtract the smaller velocity from the bigger one.
HOPE IT HELPED
Explanation:
Red dwarf and brown dwarf masses are less than a typical white dwarf mass measuring around 1.2 solar masses. But it's only a few kilometers of the radius. This is precisely because there is no force to overcome the contraction due to gravity. There is a constant battle between the external force of fusion (who wants to expand the star) and inward pressure because of gravity (who wants to compact the star) of regular stars on the main sequence. There remains a balance between these two forces as long as the star remains on the celestial equator.
Red dwarfs are helped by the nuclear fusion force, but brown dwarfs were not large enough to cause the fusion of hydrogen, they are massive enough to generate sufficient energy in the core by fusing deuterium to sustain their volume. However as soon as the star runs out of hydrogen to burn it weakens the force of the external fusion and gravity starts to compact the center of the star. The contraction heats up the core into more massive stars and helium fusion begins, rendering the star once again stable. However this helium fusion does not occur in stars with masses below 1.44Mo. Tightness persists for such stars until the star's gasses degenerate.
