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adelina 88 [10]

2 years ago

6

What do you understand by the statement-The heat of vaporization of water is about 2,260 kJ/kg

2 answers:

Verdich [7]2 years ago

8 0

Answer:The statement "The latent heat of vaporization of water is 226kj/kg." means the amount of heat energy needed to convert one kilogram of water from the liquid phase to vapor is 226kj/kg. Here, the term "latent" refers to a phase-changing process and the term "vaporization" refers to the phase change from liquid to gas

Explanation:

Mice21 [21]2 years ago

3 0

Answer:

The latent heat of vaporization of water is 226kj/kg." means the amount of heat energy needed to convert one kilogram of water from the liquid phase to vapor is 226kj/kg. Here, the term "latent" refers to a phase-changing process and the term "vaporization" refers to the phase change from liquid to gas

Explanation:

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In a tank full of water, the pressure on a surface 2 meters below the water level is 1.5 kPA. What's the pressure on a surface 6

Lina20 [59]

Answer:

P = 40.7kPa

Explanation:

To find the pressure on a surface 6 meter below you use the following formula, which takes into account the heights in which pressures are measured and also the density of the fluid and the gravitational acceleration:

$P_2-P_1=-\rho g(y_2-y_1)$ (1)

P2: pressure for a height of -6 m = ?

P1: pressure for a height of -2 m = 1.5kPa = 1500 Pa

ρ: density of water = 1000kg/m^3

g: gravitational acceleration = 9.8 ms^2

y2: -6m

y1: -2m

(the height is measure from the water level, because of that, the heights are negative)

You solve the equation (1) for P1:

$P_1=P_2-\rho g(y_2-y_1)$ (2)

Next, you replace the values of all variables in equation (2):

$P_2=1500Pa-(1000kg/m^3)(9.8m/s^2)(-6-(-2))m=40700Pa\\\\P_2=40.7kPa$

hence, the pressure on a surface 6 m below the water level is 40.7kPa

5 0

2 years ago

Sally is trying to lift a heavy box, but is not strong enough to lift it. Would the force that she is applying to the box be an

mestny [16]

If you give it unbalanced force it would go up and if you can't give it enough it will stay a balanced force

3 0

2 years ago

How much KE does the car have if it weighs 450kg and moves at the speed of 23 m/s?

Ray Of Light [21]

Answer:-The formula of to calculate KE = 1/2 m v^2

so we,

KE = 1/2 (450kg)(23m/s)^2

KE = 1/2 ×238050

KE = 119025

Explanation: In Physics Formulas mean everything.

5 0

2 years ago

A viscous liquid of constant density 500 kg/m3 and viscosity 10 Pa s falls down with constant velocity due to gravity in a long

Alekssandra [29.7K]

Answer:

$\tau=$ 2452.5 N/m^2

Explanation:

given:

density $\rho$ =500kg/m^3

viscosity $\mu$ = 10 Pa-s

diameter of tube= 2 m

and L be length

since gravity is the only force shear force will balance it

so we can write

mg= $\tau\times A$

A= $\rho\times\frac{\pi}{4} d^2\times L$

m= $\rho\times\frac{\pi}{4} d^2\times L$

therefore

$\rho\times\frac{\pi}{4} d^2\times Lg= \tau\times{\pi} d\times L$

putting values we get

$\ 500\times\frac{\pi}{4} 2^2\times g= \tau\times{\pi}\times 2$

calculating we get $\tau=$ 2452.5 N/m^2

6 0

3 years ago

The rigid link is supported by a pin at A and two A-36 steel wires, each having an unstretched length of 12 in. and cross-sectio

Leokris [45]

Answer:

Extension of the wire is not indicated

Explanation:

Young modulus (YM)= (stress/Strain); Tensile Stress/tensile Strain

=> YM *Strain =Stress=F/A; A is cross sectional area and F is the force

(YM * Strain * A)/36 =F (Force developed in each wire)

F = (350 *e*0.0125)/12

4 0

2 years ago