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3 years ago

What do you understand by the statement-The heat of vaporization of water is about 2,260 kJ/kg

2 answers:

8 0

Answer:The statement "The latent heat of vaporization of water is 226kj/kg." means the amount of heat energy needed to convert one kilogram of water from the liquid phase to vapor is 226kj/kg. Here, the term "latent" refers to a phase-changing process and the term "vaporization" refers to the phase change from liquid to gas

Explanation:

Mice21 [21]3 years ago

3 0

Answer:

The latent heat of vaporization of water is 226kj/kg." means the amount of heat energy needed to convert one kilogram of water from the liquid phase to vapor is 226kj/kg. Here, the term "latent" refers to a phase-changing process and the term "vaporization" refers to the phase change from liquid to gas

Explanation:

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9. Luke is an astronaut that moves his position in the space shuttle by climbing a

BartSMP [9]

Explanation:

Remember that power is defined as how much Work is done per unit of time.

$P = \frac{dW}{dt}$

Work is defined as the amount of force applied across a certain distance.

$W = F*d$

Since in both cases of climbing the ladder (on Earth and the moon), Luke coveres the same amount of <em>distance </em>in the same amount of <em>time</em>, we are only left with one difference between the two cases - gravity.

If you were to carry your backpack on the moon with the same load of text books, it would take less force to pick it up on the moon. Therefore, Luke expends less effort on the environment with less gravity - the moon.

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3 years ago

Read 2 more answers

The magnetic field inside a 5.0-cm-diameter solenoid is 2.0 T and decreasing at 5.00 T/s. Part A) What is the electric field str

Veronika [31]

Answer:

(A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is $3.75\times10^{-2}\ V/m$ .

Explanation:

Given that,

Magnetic field = 2.0 T

Diameter = 5.0 cm

Rate of decreasing in magnetic field = 5.00 T/s

(A). We need to calculate the electric field strength inside the solenoid at a point on the axis

Using formula of electric field inside the solenoid

$E=\dfrac{r}{2}|\dfrac{dB}{dt}|$

Electric field on the axis of the solenoid

Here, r = 0

$E=\dfrac{0}{2}\times5.00$

$E = 0$

The electric field strength inside the solenoid at a point on the axis is zero.

(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis

Using formula of electric field inside the solenoid

$E=\dfrac{r}{2}|\dfrac{dB}{dt}|$

$E=\dfrac{1.50\times10^{-2}}{2}\times|5.00|$

$E=0.0375= 3.75\times10^{-2}\ V/m$

Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.

(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is $3.75\times10^{-2}\ V/m$ .

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4 years ago