A thin metal disk of mass m=2.00 x 10^-3 kg and radius R=2.20cm is attached at its center to a long fiber. When the disk is turn
ed from the relaxed state through a small angle theta, the torque exerted by the fiber on the disk is proportional to theta. Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency w of small, free oscillations. The disk, when twisted and released, oscillates with a period T of 1.00 s. Find the torsional constant k of the fiber.
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Answer:
Explanation:
The power needed to make the escalator working is obtained by means of the Work-Energy Theorem:
The mechanical efficiency of the escalator is:
Answer:
44027.28 Joules
Explanation:
We know that Potential Energy of a body of mass 'm' is given by
where
g= acceleration due to gravity with value = 9.81
h = height above the ground level
Applying given values in the formula we get
Thus