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swat32
3 years ago
6

Anything that is made to meet a need or desire is?

Engineering
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

I think it is process or technology

shutvik [7]3 years ago
4 0

Answer:

Technology

Explanation:

It’s made to meet desire

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liberstina [14]
More work getting done and faster
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The mean of 10 numbers is 9, then the sum (total) of these numbers will be​
qwelly [4]

Answer:

90

Explanation:

mean is basically taking the sum of all numbers and then dividing the sum with the number of all given numbers..

here, the mean is 9, total numbers are 10.. so the sum will be 9 multiplied by 10, that is 90.

5 0
3 years ago
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THE MASS FOR OBJECT 1 is 107.01 grams what is the objects force in Newton’s answer please
Aleksandr [31]

Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

5 0
3 years ago
Theo Anh / Chị, để đáp ứng yêu cầu phát triển nền kinh tế thị trường định hướng Xã hội Chủ nghĩa ở Việt Nam trong bối cảnh thời
yawa3891 [41]
Nền kinh tế thị trường định hướng xã hội chủ nghĩa là nền kinh tế hàng hoá nhiều thành phần do thị trường điều tiết, bao gồm sở hữu tư nhân, tập thể và nhà nước về tư liệu sản xuất. Tuy nhiên, khu vực nhà nước và các doanh nghiệp thuộc sở hữu tập thể tạo thành xương sống của nền kinh tế.


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5 0
3 years ago
If an object is near the surface of the earth the variation of its weight with distance from the center of the earth can ofteb b
zalisa [80]

Answer:

h=32.1 km

Explanation:

<em>solution:</em>

using newton law of gravitational attraction and newton second law:

W=\frac{Gmm_{E} }{r^{2} } \\a=\frac{Gm_{E}}{r^{2}} \\W=ma\\

m_{E}= mass of earth

r= distance between two masses

at sea level

a=g

r=R_{E}

a=\frac{Gm_{E}}{r^{2}}.............................(1)

Gm_{E} =gR_{E}^2.........................(2)

by substituting (2) and (1) a=g\frac{R_{E}^2 }{r^{2} } acceleration due to gravity at a distance r from the centre of the earth in terms of g (sea level)

so the weight of the object at a distance r from the centre of the earth (W=ma)

W=mg(Re^2/r^2)..........(3)

h the height above the surface of the earth: r=Re+h

putting the value of r in eq (3)

W=mg(Re/Re+h)^2

W=0.99 mg

solving for height h:

h=Re(1/√0.99)-(1))

h=32.1 km

4 0
3 years ago
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