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aksik [14]
3 years ago
11

Describe the basic mechanism by which positive photolithography transfers a pattern, and comment on the chemical interactions of

the resist throughout the entire process.
Engineering
1 answer:
ankoles [38]3 years ago
6 0

Photo-lithography is the method of giving geometric shapes on a mask to the surface of a silicon wafer.

<u>Explanation:</u>

The fabrication of an integrated circuit (IC) requires a variety of physical and chemical processes conducted on a semiconductor (e.g., silicon) substrate. In common, the numerous methods used to create an IC fall into three divisions: film deposition, patterning, and semiconductor doping.

Films from both conductors (such as polysilicon, aluminum, and extended recently copper) and nonconductors (various forms of silicon dioxide, silicon nitride, and others) are utilized to combine and separate transistors and their parts.

Selective doping of different regions of silicon permits the conductivity of the silicon to be altered with the application of voltage. By building structures of these various parts millions of transistors can be assembled and wired together to form the complex circuitry of a modern microelectronic device.  

Fundamental to all of these methods is lithography, i.e., the development of three-dimensional relief images on the substrate for subsequent transfer of the model to the substrate.

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There are two types of cellular phones, handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles. P
nexus9112 [7]

Answer:

A) P(W) = 0.5

B) P(MF) = 0.3

C) P(H) = 0.6

Explanation:

We are told that there are two types of cellular phones which are handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles.

Also, Phone calls can be classified by the traveling speed of the user as fast (F) or slow (W).

Thus, the sample space is combination of types and classification we are given and it is written as;

S = {HF, HW, MF, MW}

A) Now, phones can either be fast(F) or slow(W). Thus, we can write;

P(F) + P(W) = 1

We are given P(F) = 0.5

Thus;

0.5 + P(W) = 1

P(W) = 1 - 0.5

P(W) = 0.5

B) Now, from the problem statement, a phone call can either be made with a handheld(H) or mobile(M). Thus the sample space partition is {H, M} and we can express as;

P(H ∩ F) + P(M ∩ F) = P(F)

We are given P[F] = 0.5 and P[HF] = 0.2.

P(H ∩ F) is same as P[HF]

Also, P(M ∩ F) is same as P(MF)

Thus;

0.2 + P(MF) = 0.5

P(MF) = 0.5 - 0.2

P(MF) = 0.3

C) Similarly, mobile Phone calls can either be fast or slow. It means the sample space partition is {F, W}

Thus;

P(M) = P(MW) + P(MF)

P(M) = 0.1 + 0.3

P(M) = 0.4

Now, since cellular phones can either be handheld(H) or Mobile(M), then we can say;

P(H) + P(M) = 1

P(H) + 0.4 = 1

P(H) = 1 - 0.4

P(H) = 0.6

5 0
3 years ago
A pipe produces successive harmonics at 300 Hz and 350 Hz. Calculate the length of the pipe and state whether it is closed at on
MAXImum [283]

Answer:

The pipe is open ended and the length of pipe is 3.4 m.

Explanation:

For identification of the type of pipe checking the successive frequencies in both the open pipe and closed pipe as below

Equation for nth frequency for open end pipe is given as

f_n=\frac{nv}{2L}

For (n+1)th value the frequency is

f_{n+1}=\frac{(n+1)v}{2L}

Taking a ratio of both equation and solving for n such that the value of n is a whole number

\frac{f_{n+1}}{f_n}=\frac{\frac{(n+1)v}{2L}}{\frac{nv}{2L}}\\\frac{350}{300}=\frac{(n+1)}{n}\\350n =300n+300\\50n =300\\n =6\\

So n is a whole number this means that the pipe is open ended.

For confirmation the  nth frequency for a closed ended pipe is given as

f_n=\frac{(2n+1)v}{4L}

For (n+1)th value the frequency is

f_{n+1}=\frac{(2n+3)v}{4L}

Taking a ratio of both equation and solving for n such that the value of n is a whole number

\frac{f_{n+1}}{f_n}=\frac{\frac{(2n+3)v}{2L}}{\frac{(2n+1)v}{2L}}\\\frac{350}{300}=\frac{(2n+3)}{(2n+1)}\\700n+350 =600n+900\\100n =550\\n =5.5\\

As n is not a whole number so this is further confirmed that the pipe is open ended.

Now from the equation of, with n=6, v=340 m/s and f=300 Hz

f_n=\frac{nv}{2L}\\300=\frac{6 \times 340}{2L}\\L=\frac{2040}{600}\\L=3.4 m

The value of length is 3.4m.

5 0
3 years ago
(a) Differentiate between heat treatment of ferrous and non-ferrous alloys (b) With your understanding of material's thermal pro
liubo4ka [24]

Answer:

In ferrous metal iron present but on the other hand in the non ferrous material iron does not present.That is why there is a different heat treatment process for ferrous and nonferrous materials.

Ferrous materials contains iron is the main constitute.Like steel ,cast iron ,wrought iron .Steel and cast iron are  the alloy element of iron ans carbon.Wrought iron is the purest from of iron.

Heat treatment process for  ferrous materials :

1.Normalizing

2.Annealing

3.Quenching

4.Surface hardening

Heat treatment process for non ferrous materials :

Mostly annealing process is used for non ferrous materials.After annealing non ferrous will become soft.

When two metal plates are joined then they form a bimetallic structure.The bimetallic structure is used to find the relationship of thermal temperature and the mechanical displacement.

The use of bimetallic structure -In clock ,thermometers ,engines.

7 0
3 years ago
According to the model rules section 240.15, rules of professional conduct, licensed professional engineers are obligated to:___
Sedaia [141]

Answer:

Option C (practice by..............technical) would be the appropriate choice.

Explanation:

  • A prerogative seems to be the discipline or nature of the design process to ensure.
  • All certificates must, therefore, throughout compliance with current requirements including professional competence, express one's right and privilege of providing offers perhaps throughout the areas of qualified professionals.

Some other alternatives that are given aren't connected to a particular scenario. But that's the best solution above.

7 0
3 years ago
How can you drop two eggs the fewest amount of times, without them breaking?
qwelly [4]
You can use like a thickish paper but not to heavy and do it spiral and fall it with bubble paper and light things and then you spin it while you drop and it won’t crack
7 0
3 years ago
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