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koban [17]
3 years ago
6

A basket of 40 pairs of pliers at a discount hardware store includes 5 pairs of 6-inch pliers. A second basket contains 20 hamme

rs, including 3 large hammers. What is the probability of drawing a 6-inch pair of pliers from the first basket without looking?
Mathematics
2 answers:
Kryger [21]3 years ago
4 0
First, add all the numbers together, which is 68. Then divided 100 by 68, which gives you the number 1.47, and that's your answer.
Ket [755]3 years ago
4 0

Answer: Our required probability is \frac{1}{8}

Step-by-step explanation:

Since we have given that

Number of pairs of pilers = 40

Number of pairs of 6-inch pilers = 5

So, Probability of drawing a 6-inch pair of pilers from the first basket without looking is given by

\frac{\text{Number of favourable outcome}}{\text{ Total number of outcomes}}\\\\=\frac{5}{40}\\\\=\frac{1}{8}

Because in another basket of hammers, there is no pilers.

Hence, our required probability is \frac{1}{8}

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Dmitry_Shevchenko [17]

Answer:

\huge\boxed{\bf\:1}

Step-by-step explanation:

\frac{ x  ^ { 2  }  -4x+3  }{ x  ^ { 2  }  -7x+12  }   \times   \frac{ x  ^ { 2  }  +2x-24  }{ x  ^ { 2  }  +5x-6  }    ^ {   }

Take \frac{ x  ^ { 2  }  -4x+3  }{ x  ^ { 2  }  -7x+12  } & factorise it at first.

\frac{ x  ^ { 2  }  -4x+3  }{ x  ^ { 2  }  -7x+12  }   \\= \frac{\left(x-3\right)\left(x-1\right)}{\left(x-4\right)\left(x-3\right)}\\= \frac{x-1}{x-4}

Now factorise the next set : \frac{ x  ^ { 2  }  +2x-24  }{ x  ^ { 2  }  +5x-6  }    ^ {   }.

\frac{ x  ^ { 2  }  +2x-24  }{ x  ^ { 2  }  +5x-6  }    ^ {   }\\= \frac{\left(x-4\right)\left(x+6\right)}{\left(x-1\right)\left(x+6\right)}\\=  \frac{x-4}{x-1}

Now, multiply the two simplified results.

\frac{ x  ^ { 2  }  -4x+3  }{ x  ^ { 2  }  -7x+12  }   \times   \frac{ x  ^ { 2  }  +2x-24  }{ x  ^ { 2  }  +5x-6  }    ^ {   }\\= \frac{x-1}{x-4}\times \frac{x-4}{x-1} \\= \frac{\left(x-1\right)\left(x-4\right)}{\left(x-4\right)\left(x-1\right)} \\= \boxed{\bf\: 1}

\rule{150pt}{2pt}

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