<u>Given</u>:
Wavelength (λ) of the laser pulse = 545 nm = 5.45 * 10⁻⁹ m
Total energy of pulse = 4.85 mJ
<u>To determine:</u>
The number of photons in the laser of a given energy
<u>Explanation:</u>
Energy per photon (E) = hc/λ
where h = planck's constant = 6.626 *10⁻³⁴ Js
C = speed of light = 3*10⁸ m/s
λ = wavelength
E = 6.626 *10⁻³⁴ Js* 3*10⁸ms-1 /5.45 * 10⁻⁹ m = 3.65 * 10⁻¹⁹ J
Now,
# photons = total energy/Energy per photon
= 4.85 * 10⁻³ J* 1 photon / 3.65 * 10⁻¹⁹ J = 1.32 * 10¹⁶ photons
Ans: the laser pulse contains 1.32 * 10¹⁶ photons
Both cyclic and noncyclic pathways operate to varying degrees during photosynthesis. Since the non-cyclic pathway produces both ATP and NADPH explain the<span> purpose of the cyclic pathway of the electron flow. ... </span>Explain how the independence of photosystem<span> l </span>gives a mechanism<span> for the evolution of the photosynthetic pathway.</span>
Albert Einstein wrote this quote. Given that he was a scientist, he found the world of religion beautiful. The mystery of life. Almost every religion out there contradicts itself but still believes in something so supernatural that they have come to rule the universe. It is a reflection of the universe which we cannot perceive. The beautiful mystery not only is the world of religion but the very structure of it. Even as a scientist – someone who believed that the world may be more functional scientifically rather than being controlled by the religious beliefs of people – if you can't stand in awe and wonder at the mystery of life, then you are in a position of great danger as you live a life you don't even wonder about. "His eyes are closed", meaning he is walking blindly through life not trying to understand the beautiful mystery of life that comes with living it.
Hope that helped. If you want to change some of the words to make it sound more grade 6 level, you are welcome to do so.
Answer:
After the reaction, there will 0.60 g of magnesium oxide and 0.25 g of oxygen gas present in the tube
Explanation:
Equation of the reaction between magnesium and oxygen is given as follows:
2Mg(s) + O₂(g) ---> 2MgO(s)
From the equation of reaction, 2 moles of magnesium reacts with i mole of oxygen gas to produce 1 mole of magnesium oxide
molar mass of magnesium is 24.0 g; molar mass of oxygen gas = 32.0 g; molar mass of magnesium oxide = 40.0 g
Therefore 24 g of magnesium reacts with 32 g of oxygen gas
I.00 g of magnesium will react with (24.0 / 32.0) * 1.00 g of oxygen = 0.75 g of oxygen gas.
Therefore, magnesium is the limiting reagent. Once it is used up, the reaction will stop and the excess oxygen will be left in the tube together with the product, magnesium oxide.
mass of excess oxygen = 1.00 - 0.75 = 0.25 g
mass of magnesium oxide formed = (24.0 / 40.0 g) * 1 = 0.60 g
Answer:
( About ) 0.03232 M
Explanation:
Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / []"
This formula would be true for the following information -
{ = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }
________
Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6
1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X
1 / [X] = 28.8 + 1 / ( 0.467 ),
1 / [X] = 28.8 + 2.1413...,
1 / [X] = 31,
[X] = 1 / 31 = ( About ) 0.03232 M
Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M