3H2+N2→2NH3
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
That statement is false
If the gaseous water molecules were greater than the liquid molecules ( which commonly happened if the temperature of the water is increased) , the water will evaporate
Explanation:
The given data is as follows.
X = 12 g, Volume of water = 2 L,
Hence, solubility will be calculated as follows.

= 6 g/L
As we know that 1 L contains 1000 ml. Hence, the calculated solubility will be converted into g/ml as follows.
Solubility = 
= 0.006 g/ml
Thus, we can conclude that the solubility of compound X in
is 0.006 g/ml.