Milk. Everything else is a compound/alloy.
Answer is: 51.047 grams <span>of sodium azide are required.
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Balanced chemical reaction: 2NaN₃(s) → 2Na(s) + 3N₂<span>(g).
m(</span>N₂) = 33.0 g; mass of nitrogen,
M(N₂) = 28 g/mol; molar mass of nitrogen.
n(N₂) = 33 g ÷ 28 g/mol.
n(N₂) = 1.178 mol; amount of substance.
From chemical reaction: n(N₂) : n(NaN₃) = 3 : 2.
n(NaN₃) = 2 · 1.178 mol ÷ 3.
n(NaN₃) = 0.785 mol.
M(NaN₃) = 65 g/mol.
m(NaN₃) = n(NaN₃) · M(NaN₃).
m(NaN₃) = 0.785 mol · 65 g/mol.
m(NaN₃) = 51.047 g.
I cant really read it you should have typed it
