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Firdavs [7]
3 years ago
14

Evan and Luke see 8 worms on the path. Luke sees 2 more worms than Evan. Even sees 3 worms.How many worms does Luke see? 10 is m

y answer. What's yours?
Mathematics
1 answer:
Lina20 [59]3 years ago
7 0

Answer:

Luke saw 5 worms

Step-by-step explanation:

Evan and Luke saw 8 worms on the path.

Evan saw 3 worms while Luke saw 2 Worms more than Evan.

So luke is +2 of Evan

Luke= 3+2

Luke = 5

Luke saw a total of 5 worms while Evan saw a total of 3 worms adding up to a total of 8 worms

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If x=-5 what is the value of x^2-1/x+1? A. 6 b. -4 c. 4 d. 5 4/5 e. 19 <br> need answers asap
xxTIMURxx [149]

Answer:

The answer is -6 but its not in the option

Step-by-step explanation:

\frac{ {x}^{2} - 1 }{ x  + 1}

Let x = -5

[(-5)²-1]/(-5+1)

= (25-1)/(-4)

= 24/-4

= -6

4 0
2 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
2 years ago
Ramon travels 20 miles in 20 minutes, how many miles can he travel in 120 minutes?
Elis [28]

Answer: 120

Step-by-step explanation:

20 divided by 20 is 1.

We have to multiply this by 120.

120 x 1 = 120. It is the answer.

4 0
2 years ago
A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels
AURORKA [14]
\boxed {\boxed { \text {Distance = Speed x Time}}}

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x 
Distance = Time x Speed = 9x

<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60

<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph

Answer: The spend of the two trains are 60 mph and 108 mph.
3 0
3 years ago
Pls answer asapppddddddd
kvv77 [185]

Answer:

<em><u>don't </u></em><em><u>know</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

<em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
2 years ago
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