A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.
<h3>What is a combustion reaction?</h3>
A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:
CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol
The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.
So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol
Therefore, -3115 kJ/mol of heat is released.
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1) <u>Stereo-selective (or enantioselective)</u> reactions form predominately or exclusively one enantiomer.
2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.
3) <u>Hydrogenation (or reduction)</u> of an alkene forms an alkane by addition of H₂.
4) <u>Dihydroxylation</u> is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.
5) <u>oxidative</u> cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.
6) <u>Regioselective</u> reactions form predominately or exclusively one constitutional isomer.
7) <u>Syn</u> dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.
Answer:
Native Elements; Metallic Elements
Explanation:
<h3>
Answer:</h3>
12.387 moles
<h3>
Explanation:</h3>
We are given;
Temperature of chlorine, T = 120°C
But, K = °C + 273.15
Therefore, T = 393.15 K
Pressure, P = 33.3 Atm
Volume, V = 12 L
We are required to calculate the number of moles of chlorine gas,
To find the number of moles we are going to use the ideal gas equation;
PV = nRT
R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore, rearranging the formula;
n = PV÷RT
Hence;
n = (33.3 atm × 12 L) ÷ (0.082057 × 393.15 K)
= 12.387 moles
Therefore, the number of moles of chlorine are 12.387 moles
