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Brut [27]
3 years ago
8

Someone help me out with these chemistry (stoichiometry)

Chemistry
1 answer:
lana66690 [7]3 years ago
6 0

Answer:Videos

For example, when oxygen and hydrogen react to produce water, one mole of oxygen ... These conversion factors state the ratio of reactants that react but do not tell ... In a typical chemical equation, an arrow separates the reactants on the left ... For example, to determine the number of mol

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What is carbon sink and how it effects our environment?
Ronch [10]

Answer:

Explanation:

Carbon sink is basically anything that absorbs carbon from the atmosphere.   Particularly, the soil, trees, plants and the ocean absorb the most carbon, which helps with greenhouse emission.

5 0
2 years ago
What is electroluminescence? Give one example.​
vredina [299]

Answer:

electroluminescence is a production of light by the flow of electrons, as within certain crystals. An example is at most resataurants with a bright sign that either says open or closed.

Explanation:

5 0
3 years ago
How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr
JulsSmile [24]

Answer: 403ml

Explanation:

M=\frac{mol}{L}

Solve for L;

L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L

Convert to mililiters

0.403L(\frac{1000ml}{1L})=403ml

3 0
3 years ago
How many protons (p) and neutrons (n) are in an atom of sr? 38 p, 90 n 90 p, 38 n 38 p, 52 n 52 p, 38 n?
harina [27]
Sr will always have 38 protons because that is its atomic number. Normally Sr has 38 protons and 49 neutrons yielding an atomic mass of 87. unless you are dealing with an isotope of Strontium in which 3 additional neutrons would give you the 53 neutrons in your answer, (38p, 52n).
3 0
3 years ago
An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0
3 years ago
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