Explanation:
To find the amount of product that would be formed from two or more reactants, we need to follow the following steps;
- Find the number of moles of the given reactants.
- Then proceed to determine the limiting reactant. The limiting reactant is the one in short supply which determines the extent of the reaction.
- Use the number of moles of the limiting reactant to find the number of moles of the product.
- Then use this number of moles to find the mass of the product
Useful expression:
Mass = number of moles x molar mass
There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.
<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>
The number of moles of a substance can be calculated by multiplying the molarity by the volume.
No. of moles = Molarity × volume
According to this question, 3L of a KBr solution are contained in a 0.4M.
no. of moles = 3L × 0.4M = 1.2moles
Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.
Learn more about no. of moles at: brainly.com/question/14919968
Answer:
6.564×10¹⁶ fg.
Explanation:
The following data were obtained from the question:
Mass of beaker = 76.9 g
Mass of beaker + salt = 142.54 g
Mass of salt in fg =?
Next, we shall determine the mass of the salt in grams (g). This can be obtained as follow:
Mass of beaker = 76.9 g
Mass of beaker + salt = 142.54 g
Mass of salt =?
Mass of salt = (Mass of beaker + salt) – (Mass of beaker)
Mass of salt = 142.54 – 76.9
Mass of salt = 65.64 g
Finally, we shall convert 65.64 g to femtograms (fg) as illustrated below:
Recall:
1 g = 1×10¹⁵ fg
Therefore,
65.64 g = 65.64 g × 1×10¹⁵ fg / 1g
65.64 g = 6.564×10¹⁶ fg
Therefore, the mass of the salt is 6.564×10¹⁶ fg.
Answer:
0.895 g/mL
Explanation:
Step 1: Given data
Mass of liquid Z (m): 2.763 lb
Volume of liquid Z (V): 5.93 cups
Step 2: Convert "m" to grams
We will use the relationship 1 lb = 453.59 g.
Step 3: Convert "V" to milliliters
We will use the relationship 1 cup = 236.59 mL.
Step 4: Calculate the density of the liquid Z
The density (ρ) of the liquid Z is equal to its mass divided by its volume.
Answer:
My chemistry teacher from my sophomore year.
Explanation:
I took class online last year and he was an older teacher and really didn't know how to use a computer. I asked for help multiple times and he would tell me to look the answer up. I would watch countless videos and still wouldn't understand. He ended up failing me that year and I had summer school. To this day, I dislike chemistry because of him.
