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Karolina [17]
3 years ago
15

Gasoline has a density of 0.749 g/mL. There are 454 grams in a pound and 3.7854 litres in a gallon. How many pounds does 19.2 ga

llons of gasoline weigh? Do not enter “pounds” as part of your answer.
Chemistry
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

119.9 pound

Explanation:

Given data:

Density of gasoline = 0.749 g/mL

Volume of gasoline = 19.2 gal (19.2× 37854 =72679.9 mL)

Mass = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

d = m/v

0.749 g/mL = m/ 72679.9 mL

m = 54437.25 g

gram to gallon:

54437.25/ 454

m = 119.9 pound

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A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar. part a part complete how many milligrams of sugar does the m
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5 0
3 years ago
Two moles of gas A spontaneously convert to 3 moles of gas b in a container where the temperature and pressure are held constant
erica [24]

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

<h3>What is Avogadro's law?</h3>

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

  • Initial amount of gas n₁ = 2moles
  • Initial volume v₁ = 13.9L
  • Final amount of gas n₁ = 3moles
  • Final volume v₂ = ?

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (13.9L × 3moles) / 2moles

V₂ = 41.7molL / 2mol

V₂ = 20.85L

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

Learn more about Avogadro's law here: brainly.com/question/15613065

#SPJ1

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1 year ago
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