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Karolina [17]
3 years ago
15

Gasoline has a density of 0.749 g/mL. There are 454 grams in a pound and 3.7854 litres in a gallon. How many pounds does 19.2 ga

llons of gasoline weigh? Do not enter “pounds” as part of your answer.
Chemistry
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

119.9 pound

Explanation:

Given data:

Density of gasoline = 0.749 g/mL

Volume of gasoline = 19.2 gal (19.2× 37854 =72679.9 mL)

Mass = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

d = m/v

0.749 g/mL = m/ 72679.9 mL

m = 54437.25 g

gram to gallon:

54437.25/ 454

m = 119.9 pound

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SIZIF [17.4K]

Answer:

See explanation

Explanation:

We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;

Step 1

2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)

Step 2

2NO(g) + O2(g) -------> 2NO2(g)

So, the overall reaction equation is;

2SO2(g) + O2(g) ------> 2SO3(g)

5 0
3 years ago
Find the celcius equivalent of 133 degrees Kelvin
egoroff_w [7]

Answer:

<h2>406 K</h2>

Explanation:

To convert a temperature from degree Celsius to Kelvin add 273 to the value in degree Celsius

That's

K = 273 + °C

where

K is the temperature in Kelvin

°C is the temperature in degree Celsius

From the question we have

K = 273 + 133

We have the final answer as

<h3>406 K</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


4 0
3 years ago
Electrolysis can be used for all of the following, except A. separating metals from ores. B. plating objects with metal coatings
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The answer is D. recharging batteries.

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3 years ago
The student who answers the riddle will get the prize ? underline pronoun<br>.​
mariarad [96]

answer:

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explanation:

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3 years ago
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