pH value 1 represents a solution with the lowest OH⁻ion concentration.
<u>Explanation:</u>
pH is given by the expression as the negative logarithm to the base 10 of the concentration of hydrogen ions.
pH = -log₁₀[H⁺]
If the pH is lower than 7, pH < 7 then it is acidic
If the pH = 7, then it is neutral
If the pH > 7, then it is basic
If pH is 1 then the solution is showing mostly acidic character,which is least basic in its character.
So if the pH is 1, which is most acidic and least basic solution that is lowest OH⁻ ion concentration.
Answer:
Bohr thought that electrons orbited the nucleus in circular paths; whereas in the modern view atomic electron structure is more like 3D standing waves. Bohr built upon Rutherford's model of the atom. ... He believed that electrons moved around the nucleus in circular orbits with quantised potential and kinetic energies.
Explanation:
Answer:
S4N2
Explanation:
good luck have a nice day
Method A is Convection
Method B is Conduction
Explanation:
From the problem, we can infer that method A is convection and method B is conduction.
Conduction, convection and radiation are the three main methods of heat transfer.
- Conduction and convection requires material medium to propagate.
- Radiation occurs in the absence of a material medium.
- Conduction mostly occurs in solid. Here, heat is transferred from one hot end to the cold end of the solid. The vibration of the particles in the hot end causes the transfer of kinetic energy to the cold end until thermal equilibrium is reached.
- In convection, heat is primarily transferred in fluids as a result of density differences. Convection involves the motion of the materials of the medium. Hot air is light and it rises whereas cold air is dense and it sinks.
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Answer:
Temperature increase = ΔT = 2.08 °C
Explanation:
Given data:
Energy absorbed by plant = 4200 J
Specific heat capacity of soil = 0.84 J/g°C
Mass of soil = 2400 g
How much temperature increase = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
by putting values,
4200 J = 2400 g ×0.84 J/g°C × ΔT
4200 J = 2016 J/°C × ΔT
ΔT = 4200 J / 2016 J/°C
ΔT = 2.08 °C