We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, 
moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
Metals are elements that are generally shiny when smooth and clean
Answer:
the answer is 10 times
Explanation:
because it takes 10 times as much energy -3330 j - to melt 10.0 grams of ice.
Colorimetric methods of analysis make use of Color changes in reagents to decipher the concentration of solutions.
Therefore, color completes the sentence
<h3>Colourimetric analysis</h3>
Generally, Colorimetric analysis is used to know the concentration of a chemical element in a solution while using colour indicators or reagents.
Therefore
Colorimetric methods of analysis are based on having a reagent that changes Color as a function of the concentration of the analyte.
Color
For more information on Compound
brainly.com/question/704297
