Answer:
Mass of K₂SO₄ = 12.633 g
Explanation:
The balance chemical equation for given reaction is as;
CaSO₄ + 2 K = K₂SO₄ + Ca
To solve this reaction one should first find the limiting reagent. To do so e will calculate the moles of each reactant as,
Moles of CaSO₄ = Given Mass / M.Mass of CaSO₄
Moles of CaSO₄ = 9.87 g / 136.14 g/mol
Moles of CaSO₄ = 0.0725 moles
Similarly for K,
Moles of K = Given Mass / A.Mass of K
Moles of K = 12.05 g / 39.10 g/mol
Moles of K = 0.308 moles
Now, according to equation,
1 mole of CaSO₄ reacts with = 2 moles of K
So,
0.0725 moles of CaSO₄ will react with = X moles of K
Solving for X,
X = 0.0725 moles × 2 moles / 1 mole
X = 0.145 moles of K
As calculated above, we are provided with 0.308 moles of K while, we require only 0.145 moles of it so it means that K is in excess and CaSO₄ is the limiting reagent hence, CaSO₄ will control the yield of K₂SO₄.
So,
The amount of K₂SO₄ produced is calculated by first finding its moles as,
According to equation,
1 mole of CaSO₄ produced = 1 mole of K₂SO₄
So,
0.0725 moles of CaSO₄ will produce = X moles of K₂SO₄
Solving for X,
X = 0.0725 moles × 1 mole / 1 mole
X = 0.0725 moles of K₂SO₄
Now convert moles of K₂SO₄ to mass as,
Mass of K₂SO₄ = Moles × M.Mass
Mass of K₂SO₄ = 0.0725 × 174.26 g/mol
Mass of K₂SO₄ = 12.633 g
