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4 years ago

A fuel cell designed to react grain alcohol with oxygen has the following net reaction:

Chemistry

1 answer:

sertanlavr [38]4 years ago

8 0

Answer:

b. E = 2,28V

Explanation:

The maximum work is the same than ΔG. As ΔG could be written as:

ΔG = nFE (1)

Where n is moles of electrons transferred, F is faraday constant (96485 J/Vmol) and E is the voltage of the cell.

For the reaction:

CH₃OH(l) + ³/₂O₂(g) → CO₂(g) + 2H₂O(l)

The oxidation state of C in CH₃OH is -2 but in CO₂ is +4, that means transferred electrons are +4 - -2 = 6e⁻

Replacing in (1):

1320x10³ J = 6mol e⁻×96485J/Vmol×E

E = 2,28V

I hope it helps!

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Carbon dioxide can be formed from the reaction of carbon monoxide and oxygen. How many moles of carbon monoxide must be reacted

dybincka [34]

Answer:

you know answer?

Explanation:

5 0

4 years ago

(Brainliest) Please Help! Please do not give me a random, gibberish answer or I will report you and give you a low rating theref

steposvetlana [31]

Answer:

Answer : The correct answer for mass of KBr = 2.53 g

Given :

Molarity of KBr solution = 0.85 M

Volume of KBr solution = 25 mL

Converting volume from mL to L ( 1 L = 1000 mL )

Volume of solution = 25 mL * \frac{1 L }{1000mL}Volumeofsolution=25mL∗

1000mL

Volume of solution = 0.025 L

Mass of KBr = ?

Mass of KBr can be calculated using following steps :

1) To find mole of Kbr :

Mole of KBr can be calculated using molarity .

Molarity : It is defined as mole of solute present in volume of solution in Liter .

It uses unit as M or \frac{mol}{L}

mol

It can be expressed as :

Molarity = \frac{mol of solute (mol)}{volume of solution (L)}Molarity=

volumeofsolution(L)

molofsolute(mol)

Plugging value of molarity and volume

0.85 \frac{mol}{L} = \frac{mol of Kbr}{0.025 L}0.85

mol

0.025L

molofKbr

Multiplying both side by 0.025 L

0.85 \frac{mol}{L} * 0.025 L = \frac{mole of KBr}{0.025 L} * 0.025 L0.85

mol

∗0.025L=

0.025L

moleofKBr

∗0.025L

Mole of KBr = 0.02125

2) To find mass of Kbr :

Mass of Kbr can be calculated using mole . Mole can be expressed as :

Mole (mol) = \frac{mass (g) }{molar mass \frac{g}{mol} }Mole(mol)=

molarmass

mol

mass(g)

Mole of Kbr = 0.02125 mol

Molar mass of KBr = 119.00 \frac{g}{mol}

mol

Plugging values in mole formula

0.02125 mol = \frac{mass (g)}{119.00 \frac{g}{mol}}0.02125mol=

119.00

mol

mass(g)

Multiplying both side by 119.00 \frac{g}{mol}

mol

0.02125 mol * 119.00 \frac{g}{mol} = \frac{mass (g)}{119.00 \frac{g}{mol}} * 119.00\frac{g}{mol}0.02125mol∗119.00

mol

119.00

mol

mass(g)

∗119.00

mol

Mass of KBr = 2.53 g

6 0

3 years ago

Rank the elements in each of the following sets in order of increasing IE₁:

zavuch27 [327]

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.

But when we move from top to bottom in a group then there occurs an increase in size of the atoms. Hence, ionization energy decreases along a group.

(a) As Sb, Sn and I are all period 5 elements. Hence, these elements are arranged in order of increasing $IE_{1}$ as follows.

Sn < Sb < I

(b) As Sr, Ca, and Ba are all elements of group 2a. Hence, these elements are arranged in order of increasing $IE_{1}$ as follows.

Ba < Sr < Ca

3 0

3 years ago

A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Cel

Mariulka [41]

Answer:

T₂ = 182 K

Explanation:

Given that,

Initial pressure, P₁ = 120 kPa

Initial temperature, T₁ = 0˚C = 273 K

We need to find the final temperature when the pressure is 80 kPa.

We know that, Gay Lussac's Formula is :

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{80\ kPa\times 273}{120\ kPa}\\\\T_2=182\ K$

So, the new temperature is equal to 182 K.

4 0

3 years ago

Identify indicators of a chemical reaction. Check all of the boxes that apply.

Marina CMI [18]

All except for absorption of heat

4 0

1 year ago