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Anna71 [15]
3 years ago
14

A fuel cell designed to react grain alcohol with oxygen has the following net reaction:

Chemistry
1 answer:
sertanlavr [38]3 years ago
8 0

Answer:

b. E = 2,28V

Explanation:

The maximum work is the same than ΔG. As ΔG could be written as:

ΔG = nFE <em>(1)</em>

Where n is moles of electrons transferred, F is faraday constant (96485 J/Vmol) and E is the voltage of the cell.

For the reaction:

CH₃OH(l) + ³/₂O₂(g) → CO₂(g) + 2H₂O(l)

The oxidation state of C in CH₃OH is -2 but in CO₂ is +4, that means transferred electrons are +4 - -2 = <em>6e⁻</em>

Replacing in (1):

1320x10³ J = 6mol e⁻×96485J/Vmol×E

<em>E = 2,28V</em>

<em></em>

I hope it helps!

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A 50.0 g sample of liquid water at 25.0 degree C is mixed with 29.0 g of water at 45 degree C. The final temperature of the wate
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<u>Answer:</u> The final temperature of water is 32.3°C

<u>Explanation:</u>

When two solutions are mixed, the amount of heat released by solution 1 (liquid water) will be equal to the amount of heat absorbed by solution 2 (liquid water)

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

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m_2 = mass of solution 2 (liquid water) = 29.0 g

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T_1 = initial temperature of solution 1 = 25°C  = [273 + 25] = 298 K

T_2 = initial temperature of solution 2 = 45°C  = [273 + 45] = 318 K

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Putting values in equation 1, we get:

50.0\times 4.18\times (T_{final}-298)=-[29.0\times 4.18\times (T_{final}-318)]\\\\T_{final}=305.3K

Converting this into degree Celsius, we use the conversion factor:

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Hence, the final temperature of water is 32.3°C

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