Answer:
N,N-dimethylacetamide is formed.
Explanation:
- It is an example of a nucleophilic addition-elimination reaction. Here dimethylamine acts as a nucleophile.
- In the first step, dimethyl amine gives nucleophilic addition reaction at carbonyl center of acetyl chloride.
- In the second step, removal of Cl atoms occurs.
- In the third step, deprotonation takes place from amino group to produce N,N-dimethylacetamide.
- Full reaction mechanism has been shown below.
It is made of only nonmetals is not true because there are other elements that form it.
Answer:
Explanation: In my opinion law is stated as fact because it is passes through and approved by many peoples but theory is an idea someone has and is not approved and is set on a base of beliefs.
Answer: 
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.
The given chemical equation is:

The complete ionic equation is:

The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.
Thus the net ionic equation is:

Answer:
no. of water molecules associated to each molecule of
= 4
Explanation:
Mass of
before heating = 19.8 g
Mass of
after heating = 12.6 g
Difference in mass of
before and after heating
= 19.8 - 12.6 = 7.2 g
Difference in mass corresponds to mass of water driven out.
Molar mass of water = 18 g/mol
No. of moles of water = 
Mass of
obtained after heating is mass of anhydrous
.
Mass of anhydrous
= 12.6 g
Molar mass of
= 125.9 g/mol
No. of mol of anhydrous
= 
so,
0.1 mol of
have 0.4 mol of water
1 mol of
will have = 
Hence, no. of water molecules associated to each molecule of
= 4