Answer:
480.6 g
Explanation:
Given data:
Number of molecules of methanol = 9.01 ×10²⁴
Mass in gram = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ molecules
9.01 ×10²⁴molecules ×1 mol /6.022 × 10²³ molecules
1.5 ×10¹ mol
15 mol
Mass in gram:
Mass = number of moles × molar mass
Mass = 15 mol × 32.04 g/mol
Mass = 480.6 g
The formula of hydrated copper(II) sulfate is CuSO4.10H2O
<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>
The formula of the hydrated copper (ii) sulfate is determined as follows:
Mass of hydrated salt = 12.5 g
Mass of anhydrous salt = 8.0 g
Mass of water = 12.5 - 8 = 4.5 g
mole ratio of water and anhydrous salt is;
4.5/18 : 8.0/159.5
0.562 : 0.05
10 : 1
Water of crystallization (n) = 10.
Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O
Learn more about water of crystallization at: brainly.com/question/26146814
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Answer:
0.525 M CuSO
Explanation:
Molarity (M) is the units mol/L. Let's figure out how many moles of CuSO we have:
35 mL = 35/1000 L = 0.035 L
0.035 L * 1.50 mol/L = 0.0525 mol CuSO
Our new volume is 100 mL, so let's first convert this to L:
100 mL = 100/1000 L = 0.100 L
To find the new molarity, divide the number of moles (0.0525 moles) by the number of liters (0.100 L):
0.0525 mol / 0.100 L = 0.525 M CuSO
Hope this helps!
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