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lozanna [386]
3 years ago
7

The owner of an office building is expanding the length and width of a parking lot by the same amount. The lot currently measure

s 120 ft by 80 ft, and the expansion will increase its area by 4,400 ft2. By how many feet should the length of the parking lot be increased?
Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Present area = 120 * 80 = 9600 ft^2 so the new area will be 9600 + 4400 = 14000

So if increase in length = x we have

(x + 120)(x + 80) = 14,000

x^2 + 200x + 9600 - 14000 = 0

x^2 + 200x - 4400 = 0

x = 20 feet answer

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The term for a point that varies greatly from all other data points is known as an <u>OUTLIER</u>

<u></u>

Explanation:

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3 years ago
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\Delta KLJ\sim\DeltaNPM (AAA) Corresponding angles are congruent.

Therefore, the sides of the triangles are proportional:

\dfrac{4x-4}{20}=\dfrac{30}{25}    cross multiply

25(4x-4)=(20)(30)    use distributive property

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100x=500     divide both sides by 100

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\Delta PQR\cong\Delta STU (SAS)

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

Therefore we have the equation:

3y-2=y+4\qquad|+2\\\\3y=y+6\qquad|-y\\\\2y=6\qquad|:2\\\\y=3

The perimeter of △PQR:

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Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

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95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0796, which is the critical value that should be used.

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The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

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